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Akimi4 [234]
2 years ago
6

3. Hahn determined that barium (atomic number 56) was one of the elements created when a uranium atom (atomic number 92) split .

Use a periodic table to determine the other element that was created during this process.​
Physics
1 answer:
creativ13 [48]2 years ago
8 0

According to a periodic table, Krypton was created during the fission of Uranium.

<h3>What is the atomic number?</h3>

<em>Atomic</em> number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.

Thus, the fission of uranium is led by two elements with <em>atomic</em> numbers 56 and 36. According to a periodic table, those <em>atomic</em> numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.

According to a periodic table, Krypton was created during the fission of Uranium. \blacksquare

To learn more on fission, we kindly invite to check this verified question:  brainly.com/question/6572079

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A small logo is embedded in a thick block of crown glass (n = 1.52), 4.70 cm beneath the top surface of the glass. The block is
harkovskaia [24]

The concept required to solve this problem is the optical relationship that exists between the apparent depth and actual or actual depth. This is mathematically expressed under the equations.

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

Where,

d_g = Depth of glass

n_w = Refraction index of water

n_g = Refraction index of glass

n_{air} = Refraction index of air

d_w = Depth of water

I enclose a diagram for a better understanding of the problem, in this way we can determine that the apparent depth in the water of the logo would be subject to

d'w = d_w (\frac{n_{air}}{n_w})+d_g (\frac{n_{air}}{n_g})

d'w = (1.7cm) (\frac{1}{1.33})+(4.2cm)(\frac{1}{1.52})

d'w = 4.041cm

Therefore the distance below the upper surface of the water that appears to be the logo is 4.041cm

3 0
3 years ago
Mary travelled 70 miles/hour due north. This is an example of what?
kolezko [41]
I believe this would be an example of Mary's velocity. We have her speed and direction which is all you need to find velocity.
4 0
3 years ago
Read 2 more answers
Which statements describe the Mercalli scale? Check all that apply.
konstantin123 [22]
<h3><u>Full question:</u></h3>

Which statements describe the Mercalli scale? Check all that apply.

A. This scale measures seismic waves based on their size.

B. This scale rates an earthquake according to how much damage it causes.

C.This scale produces a single rating for earthquakes that reach the surface.

D. This scale uses Roman numerals to rank the damage caused by an earthquake.

E.This scale measures the magnitude of an earthquake based on the size of seismic waves.

<h3><u>Answer:</u></h3>

The Mercalli scale : This scale rates an earthquake according to how much damage it causes and This scale uses Roman numerals to rank the damage caused by an earthquake.

<h3><u>Explanation:</u></h3>

The Modified Mercalli scale is intended to illustrate the consequences of an earthquake, at a contracted station, on tangible characteristics, on modern fittings and human beings.

The Modified Mercalli Intensity value ascribed to a particular site subsequent an earthquake has an extra significant means of severity to the nonscientist than the magnitude because intensity assigns to the outcomes really encountered at that position. This scale is comprised of 12 growing levels of intensity, denoted by Roman numerals, arranging from gradual shaking to catastrophic impairment.

3 0
3 years ago
Consider a box with two gases separated by an impermeable membrane. The membrane can move back and forth, but the gases cannot p
padilas [110]

Answer:

The answer is "0.3336\ m^3"

Explanation:

Using the Promideal gas law:

P_A=P_B\\\\P_A(V_A-\eta_A b)= \eta_A RT......(1)\\\\P_B V_B=\eta_B \bar{R}T........(2)\\\\From (1) \zeta (2)\\\\  

\frac{\eta_A}{V_A-\eta_A b}=\frac{\eta B}{V B}\\\\  \frac{V A- \eta_A b}{V B}=\frac{\eta A}{\eta B }\\\\  \frac{V A-b}{V B}=\frac{1}{2}\\\\V A+V B=1\\\\V B =1- V A\\\\\frac{V A-b}{1-V A}=\frac{1}{2}\\\\2V A-2b=1-V A\\\\3 V A=1+2b\\\\V A=\frac{1+2b}{3}\\\\

      =\frac{1+2(4\times 10^{-4})}{3}\\\\=0.3336\ m^3

8 0
3 years ago
What is the force driving all of these transport mechanisms?
xenn [34]
<span>Passive Transport Passive transport is the movement of molecules across the cell membrane and does not require energy. It is dependent on the permeability of the cell membrane. There are three main kinds of passive transport - Diffusion, Osmosis and Facilitated Diffusion</span>
4 0
3 years ago
Read 2 more answers
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