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Akimi4 [234]
2 years ago
6

3. Hahn determined that barium (atomic number 56) was one of the elements created when a uranium atom (atomic number 92) split .

Use a periodic table to determine the other element that was created during this process.​
Physics
1 answer:
creativ13 [48]2 years ago
8 0

According to a periodic table, Krypton was created during the fission of Uranium.

<h3>What is the atomic number?</h3>

<em>Atomic</em> number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.

Thus, the fission of uranium is led by two elements with <em>atomic</em> numbers 56 and 36. According to a periodic table, those <em>atomic</em> numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.

According to a periodic table, Krypton was created during the fission of Uranium. \blacksquare

To learn more on fission, we kindly invite to check this verified question:  brainly.com/question/6572079

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Andrew is pushing this block to the right across on the floor. Which force in the free body diagram is pointing in the wrong dir
soldier1979 [14.2K]

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the normal force

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a 3.0 kg mass moving to the right at 1.4 m/s collides in a perfectly inelastic collision with a 2.0 kg mass initially at rest. w
Sedbober [7]

The velocity of the combined mass after the collision is 0.84 ms-1.

<u>Explanation:</u>

According to law of conservation of momentum, the change in momentum before collision will be equal to the change in momentum of the objects after collision in isolated system.

But as it is perfectly inelastic collision in the present case, the final momentum will be based on the product of total mass of both the object with the velocity with which the collision occurred. This form is attained from the law of conservation of momentum as shown below:

So as law of conservation of momentum,

                   M_{1} U_{1}+M_{2} U_{2}=M_{1} V_{1}+M_{2} V_{2}

Here M_{1} = 3 kg  and M_{2} = 2 kg are the masses of objects 1 and 2, U_{1} = 1.4 m/s  and U_{2} = 0 are the initial velocities of object 1 and object 2,  V_{1} and  V_{2} are the final velocities of the objects.

So after collision, object 1 get sticked to object 2 and move together with equal velocity V_{1} =  V_{2} = V_{f}. Thus the above equation will become,

            M_{1} U_{1}+M_{2} U_{2}=\left(M_{1}+M_{2}\right) V_{f}

So the final velocity is

              V_{f}=\frac{M_{1} U_{1}+M_{2} U_{2}}{\left(M_{1}+M_{2}\right)}

Thus,

       V_{f}=\frac{(3 \times 1.4+2 \times 0)}{(3+2)}=\frac{4.2}{5} = 0.84 ms-1.

8 0
4 years ago
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