94. The diagram shows the orbit of a satellite
1 answer:
Answer:
7.65x10^3 m/s
Explanation:
The computation of the satellite's orbital speed is shown below:
Given that
Earth mass, M_e = 5.97 × 10^24 kg
Gravitational constant, G = 6.67 × 10^-11 N·m^2/kg
Orbital radius, r = 6.80 × 10^6m
Based on the above information
the satellite's orbital speed is
V_o = √GM_e ÷ √r
= √6.67 × 10^-11 × 5.97 × 10^24 ÷ √6.80 × 10^6
= 7.65x10^3 m/s
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Answer:
Explanation:
Answer:
4.53 kg
Explanation:
spring constant, K = 16 N/m
Amplitude, A = 20 cm = 0.2 m
Maximum speed, v = 37.6 cm/s = 0.376 m/s
The formula for maximum speed is given by
v = ωA
where, ω is the angular frequency
0.376 = ω x 0.2
ω = 1.88 rad/s
m = 4.53 kg
Thus, the mass of banana bunch is 4.53 kg.