Well i think it is false caus ebunch of products these day have metals incorparded in the product
A Cyclone is a hurricane.
80000 Joule is the change in the internal energy of the gas.
<h3>In Thermodynamics, work done by the gas during expansion at constant pressure:</h3>
ΔW = -pdV
ΔW = -pd (V₂ -V₁)
ΔW = - 1.65×10⁵ pa (0.320m³ - 0.110m³)
= - 0.35×10⁵ pa.m³
= - 35000 (N/m³)(m³)
= -35000 Nm
ΔW = -35000 Joule
Therefore, work done by the system = -35000 Joule
<h3>Change in the internal energy of the gas,</h3>
ΔV = ΔQ + ΔW
Given:
ΔQ = 1.15×10⁵ Joule
ΔW = -35000 Joule
ΔU = 1.15×10⁵ Joule - 35000 Joule
= 80000 Joule.
Therefore, the change in the internal energy of the gas= 80000 Joule.
Learn more about thermodynamics here:
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Weight = (mass) x (gravity)
70 N = (mass) x (9.8 m/s²)
Divide each side by (9.8 m/s²) , and you have
mass = 70 N / 9.8 m/s² = 7.14 kg.
___________________________
Mass on the moon:
Mass doesn't change. It's a number that belongs to the bowling ball,
no matter where the ball goes. If the mass of the bowling ball is 7.14 kg
anywhere, then it's 7.14 kg everywhere ... on Earth, on the moon, on Mars, rolling around in the trunk of my car, or floating in intergalactic space.
However, WEIGHT depends on the gravity wherever the ball happens to be
at the moment.
The acceleration of gravity on the moon is 1.622 m/s².
So the WEIGHT of the ball on the moon is
(7.14 kg) x (1.622 m/s²) = 11.58 Newtons
That's only about 16% of its weight on Earth.
Answer:
550000000N/m
Explanation:
Given that a copper wire has a radius of 2.9 mm. When forces of a certain equal magnitude but opposite directions are applied to the ends of the wire, the wire stretches by 5.0×10−3 of its original length.
Original length L = 0.005L
the strain = extension/ original length
the strain = 0.005L / L
the strain = 0.005
Young modulus = stress / strain
11 × 10^10 = stress / 0.005
Cross multiply
Stress = 11 × 10^10 × 0.005
Stress = 550 000000 N/m
Therefore, the tensile stress on the wire is 550000000 N/m.
