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3 years ago

Which segment represent slowing down

Physics

2 answers:

lakkis [162]3 years ago

6 0

Answer:

A downward sloping line

Explanation:

Nezavi [6.7K]3 years ago

5 0

Answer:

Summary: A speed-

Explanation:

time graph shows us how the speed of a moving object changes with time. The steeper the graph, the greater the acceleration. A horizontal line means the object is moving at a constant speed. A downward sloping line means the object is slowing down.

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What type of power plant used heat from underground to make electricity

iren2701 [21]

That's called "<em>Geothermal</em>" energy.

"Geo ..." always means something about the Earth.

"Thermal ..." always means something about heat.

Geothermal energy is used in places where there's a lot of heat that's not too far under the ground, like in places above ancient volcanos.

The system is built with pipes running deep down into the ground and then back up again, and then running water is pumped through the pipes. The water picks up heat from down under and brings the heat up to the surface, where it can be used to heat homes and buildings, and turn steam turbines to generate electricity.

Geothermal is the MAIN source of energy in Iceland.

4 0

4 years ago

23.

Volgvan

Answer:

1 m = 100 cm....so 2.5 m = (2.5 * 100) = 250 cm

a = 1st shelf

b = 2nd

c = 3rd

d = 4th

a + b + c + d = 250

b = 2a + 18

c = a - 12

d = a + 4

a + (2a + 18) + (a - 12) + (a + 4) = 250

5a + 10 = 250

5a = 250 - 10

5a = 240

a = 240/5

a = 48 cm <== 1st shelf

b = 2a + 18 = 2(48) + 18 = 114 cm <== 2nd shelf

c = a - 12 = 48 - 12 = 36 cm <== 3rd shelf

d = a + 4 = 48 + 4 = 52 cm <== 4th shelf

so 2nd shelf is 114 cm

4 0

3 years ago

A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.

arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

Mass of the first puck = $m_1\ =\ 5\ kg$
Mass of the second puck = $m_2\ =\ 3\ kg$
initial velocity of the first puck = $u_1\ =\ 3\ m/s.$
Initial velocity of the second puck = $u_2\ =\ -1.5\ m/s.$

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

$m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.$

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = $v_2\ =\ 2.31\ m/s.$

Let $v_1$ be the final velocity of first puck after the collision.

From the conservation of linear momentum,

$m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.$

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

$v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\$

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = $25\times 10^{-3}\ sec$

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

$\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N$

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0

3 years ago

What is the average velocity if the initial velocity of an object is 10 m/s & the final velocity is 28 m/s

Likurg_2 [28]

Answer:

$v_{1} = 19 m/s$

Explanation:

$v_{1} = \frac{(v_{2} + u)}{2}$ , where $v_1$ <em> </em>= avg. velocity, $v_2$ = final velocity, and $u$ = initial velocity.

6 0

3 years ago

The volume of gas decreases at constant temperature to 80% of the inital value. How does the pressure value change relative to t

Westkost [7]

Answer:

The pressure value changes 400 % relative to the initial value.

Explanation:

Let suppose that the gas behaves ideally and represents a closed system, that is, a system with no mass interactions so that number of moles is conserved ( $n$ ). Since the variables involved in the isothermal process are pressure ( $P$ ) and volume ( $V$ ). Finally, the process is represented by the following relationship: