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hodyreva [135]
2 years ago
13

A buyer purchases 20 percent of the 22000 widgets in a warehouse's inventory. The next day, another buyer purchases 10 percent o

f the remaining widgets. How many widgets are left in the warehouse?
Mathematics
1 answer:
DanielleElmas [232]2 years ago
6 0

Answer:

15,840

Step-by-step explanation:

Multiplying 22,000 by 20% to get 4400, subtract.

Multiplying 17,600 by 10% to get 1,760, subtract.

Final answer, 15,840.

Good luck! Hope this helps!

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A rectangle has an area of 12 square feet and a length of 5 feet. What is its width?
Lera25 [3.4K]
Well, you know that the area of the rectangle is 12 square feet. And you know one of the numbers multiplied to get 12 is 5, so divide 12 by 5. You would get 2.4 as the other number needed.
In this case, 5 feet is the width and 2.4 feet is the length.
8 0
3 years ago
Read 2 more answers
Lexi2984 can u help me with this question
arsen [322]

9514 1404 393

Answer:

  see the attachment

Step-by-step explanation:

The x- and y-intercepts are easily found:

<u><em>X-intercept</em></u>

Set y = 0 and divide by the coefficient of x.

  -x +0 = 8

  x = -8

__

<u><em>Y-intercept</em></u>

Set x = 0 and divide by the coefficient of y.

  0 -2y = 8

  y = -4

__

Now, we have two points on the graph: (-8, 0) and (0, -4). A third point can be one that is halfway between these: (-4, -2). The graph is attached.

7 0
3 years ago
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
Please help! Correct answer only! This assignment is due today.
Bas_tet [7]

Step-by-step explanation:

Well they made 19 clay, where 12 were vases. That means 7 were not vases. She randomly chooses 16 clay objects, which then also means 3 were left behind. so if the vases are  12/19, which is approximately 63%, then 63% of the objects are vases. Makes sense, right? Well now we need to multiply that by the initial 11 in the question. After all of this work..

Answer: 6.9474 or 6.94736.

Please mark as Brainliest.

6 0
3 years ago
MARKING BRINLEST RIGHT NOWW HURRYY
natima [27]

Answer:

$275

Step-by-step explanation:

So she put $60 into savings....

X is the amount of her paycheck...

after buying the clothes she had X-75

She spend (2/5)(x-75)  on books

The amount deposited into saving and spent on groceries totals 120.

So

X = 75 + (2/5)(x-75) + 120

X = (2/5)(X-75) + 195

X = (2/5)X - 30 + 195

X = (2/5)X + 165

(3/5)X = 165

X = 165*5/3 = 5*55 = 275

Starts with 275

spent 75 on clothes, which makes it 200.

2/5 of 200 is 80, which makes it 120.

60 deposited into savings and 60 on groceries

Her paycheck was 275

6 0
3 years ago
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