The low melting point of the wire is utilized in making electric fuse.
Answer:
<em>0.15M</em>
Explanation:
Molar Concentration = ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D)
Assuming 20g of the unadulterated aluminium chloride was weighed into the volumetric flask, and given molar mass of AlCl3 = 133.34g/mol
∴ Molarity = ![\frac{20}{133.34}](https://tex.z-dn.net/?f=%5Cfrac%7B20%7D%7B133.34%7D)
= 0.14999 ≈ <em><u>0.15M (to 2 significant figures)</u></em>
I hope this solution is clear. The same can be calculated from concentration by volume.
The correct response would be
A. Both, the types of atoms involved and or present in the chemical substance and the arrangements of such atoms within the compound can dictate the properties of the substance.
Explanation:
A property or characteristic of a substance that's determined throughout a reaction within which the chemical composition or identity of the substance is changed. Combustibility is a crucial property to think about once selecting building materials.
(a) Calculate the molar concentration of the dil. HCl
[H+] = 10^(-pH) mol/L = 10^(-1.80) mol/L = 0.015 85 mol/L
(b) Calculate the mass of HCl in the dil. HCl
Moles of HCl = 4.90 L dil solution × (0.015 85 mol HCl/1 L dil solution)
= 0.077 66 mol HCl
MM of HCl = (1.008 + 35.45) g/mol = 36.458 g/mol
Mass of HCl = 0.077 66 mol HCl x (36.458 g HCl/1 mol HCl) = 2.831 g HCl
(c) Calculate the volume of conc. HCl
Mass of conc solution = 2.831 g HCl x (100 g conc solution/36.0 g HCl)
= 7.865 g conc solution
Volume of conc HCl
= 7.865 g conc solution × (1 mL conc HCl/1.179 g conc solution)
= 6.67 mL conc HCl