Answer:
0.0776
Step-by-step explanation:
In order to solve this problema, Baye´s rule is used. Ii is expressed as follows:
P(A if B)=(P(B if A)*P(A))/(P(B))
Let A be women who have cancer and let B be women who have positive mammographies
So, P(B if A) would be women with breast cancer get positive mammographies
P(B if A) = 0.8
P(A) would be women with breast cancer
P(A) = 0.01
P(B) would be the women with positive mammographies. We don´t know it.
In order to find it we use law of total probability
P(B) = P(positive mammographies and cancer) + P(positive mammographies without cancer)
P(B) = 0.8*.01+0.096*0.99
P(B) = 0.103
With P(B) calculated we can complete the equation:
P(A if B)=(0.8*0.01)/0.103=0.0776
Probability is 0.0776
Answer:
off topic- and I'm sorry for that- but hi stay- :)
311(1.50)+.50x=385.50
would be your equation
Answer:
C
Step-by-step explanation:
to find the first 4 terms, substitute n = 1, 2, 3, 4 into the expression
n = 1 → 1(1 - 1) - 4 = 0 - 4 = - 4
n = 2 → 2(2 - 1) - 4 = 2 - 4 = - 2
n = 3 → 3(3 - 1) - 4 = 6 - 4 = 2
n = 4 → 4(4 - 1) - 4 = 12 - 4 = 8
the first four terms are - 4, - 2, 2, 8 → C
