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BartSMP [9]
2 years ago
15

What is 2H2 + O2 2H2O in oxidation form and in reduction form?

Chemistry
1 answer:
Eva8 [605]2 years ago
7 0

In the reaction of water, 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.

<h3>What is reducing agent?</h3>

A reducing agent is a type of chemical that "donates" an electron to another atom that needs an electron. This type of reaction in which loss of electron occurs is called reduction reaction.

So we can conclude that 2H2 is oxidized to form 2H2O by gaining oxygen atom which shows that 2H2 is reducing agent as it undergoes oxidation.

Learn more about reduction here: brainly.com/question/3457976

#SPJ1

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When you burned copper, the product copper
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Answer:

Oxygen.

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Answer: Thus the solubility of N_2 gas in water, at the same temperature, if the partial pressure of gas is 10.0 atm is 235mg/100g.

Explanation:-

The Solubility of N_{2} in water can be calculated by Henry’s Law. Henry’s law gives the relation between gas pressure and the concentration of dissolved gas.

Formula of Henry’s law,  C=k_{H}P.

k_{H}= Henry’s law constant = ?

The partial pressure (P) of N_{2} in water = 4.07 atm

\C= k_{H}\times P\\95.7mg=k_{H}\times 4.07

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C= k_{H}\times P\\C=23.5\times 10.0=235mg/100mg

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How is particle motion related to thermal equilibrium?
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