I believe your answer is C.
Hope this helps!
Answer:
yield = 8501.96 g H3PO4
Explanation:
2344.44 g H20 × (1 mol H2O/18.01528 g H20)
= 130.14 mol H20
130.14 mol H2O × (4 mol H3PO4/6 mol H2O)
= 86.76 mol H3PO4
86.76 mol H3PO4 × (97.994 g H3PO4/1 mol H3PO4)
= 8501.96 g H3PO4
Answer:
your answer is b. chlorofluorocarbon(CFC
Explanation:
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Answer:
Percent yield of CO₂ is 6.25 %.
Explanation:
Given data:
Percent yield of CO₂ = ?
Actual yield of CO₂ = 28.16 g
Number of moles of C₈H₁₈ = 8.000 mol
Number of moles of O₂ = 16.00 mol
Solution:
Chemical equation:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Now we will compare the moles of C₈H₁₈ and O₂ with CO₂.
C₈H₁₈ : CO₂
2 : 16
8.000 : 16/2×8.000 = 64 mol
O₂ : CO₂
25 : 16
16 : 16/25×16= 10.24 mol
Less number of moles of CO₂ are produced from 16 moles of O₂. it will limit the yield of CO₂.
Grams of CO₂ produced:
Mass = number of moles × molar mass
Mass = 10.24 mol × 44 g/mol
Mass = 450.56 g
Percentage yield of CO₂:
Percentage yield = actual yield / theoretical yield × 100
Percentage yield = 28.16 g/ 450.56 g× 100
Percentage yield = 6.25 %
Whichever one has a negative enthalpy value.