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Ivan
2 years ago
10

You want to draw a red then a blue marble. do you have a better chance of drawing a red then blue marble with or without replaci

ng the first marble? explain your answer
Mathematics
1 answer:
elena-s [515]2 years ago
7 0

Answer: Without replacing

Step-by-step explanation:

If you don't replace the first red marble, it decreases the number of red marbles in the mix, making the proportion of blue marbles relatively larger. For example, if there were 5 red and 5 blue marbles, there would be a 50% chance of drawing a blue marble. If the red drawn is not replaced, there is a 5/9 chance of drawing a blue marble, or a 55% chance of drawing one.

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On​ Monday, a museum had 400 visitors. On​ Tuesday, it had 780 visitors. Estimate the percent change in the number of visitors t
11Alexandr11 [23.1K]

Alright, lets get started.

Numbers of visitors on Monday = 400

Numbers of visitors on Tuesday = 780

So, percentage change = \frac{780-400}{400}*100

So, percentage change  = \frac{380}{400} *100

So, percentage change = 95 %    :    Answer

If same estimated percentage increase on next day also, means on Wednesday, the number of visitor will be = 780+ 780*95%

So,number of visitors on Wednesday = 780 + 741

Number of visitors on Wednesday = 1521     :    Answer


4 0
3 years ago
So in math class we are doing Simplifying Algebraic Expressions or at least that is what the lesson is called but what is 7x +7.
Makovka662 [10]
No you can’t add them, but you can do this: 7x+7 =0
-7 -7
7=7x
/7 /7
1=x
4 0
3 years ago
Read 2 more answers
What is the surface area of a triangular pyramid if each face has an area of 50 cm2?
DIA [1.3K]
I think the answer would be A.150
7 0
3 years ago
Two water pumps are filling a pool. One of the pumps is high power and can fill the pool 5 hours before the other can do. Howeve
9966 [12]

L = hours for the slower pump to fill the pool

L - 5 = hours for the high power pump, since it can do it in 5 hours less.

since the slower pump takes L hours, the faster pump takes then L - 5 hours.

we know both pumps together take 3 hours to do <u>half of the pool</u>, so that means that to fill up <u>the whole pool it takes them 6 hours</u>.

since the slower pump can do it alone in L hours, in 1 hour it has done 1/L of the whole thing.

likewise, since the faster pump can do it in L-5 hours, in 1 hour alone it has done 1/(L-5) of the whole job.


\bf \stackrel{\textit{slower pump's rate}}{\cfrac{1}{L}}~~~~+\stackrel{\textit{faster pump's rate}}{\cfrac{1}{L-5}}~~~~=~~~~\stackrel{\textit{total done in 1 hour}}{\cfrac{1}{6}} \\\\\\ \textit{let's multiply both sides by }\stackrel{LCD}{6(L)(L-5)}\textit{ to do away with the denominators} \\\\\\ 6(L)(L-5)\left( \cfrac{1}{L}+\cfrac{1}{L-5} \right)=6(L)(L-5)\left( \cfrac{1}{6} \right)


\bf 6(L-5)+6L=(L)(L-5)\implies 6L-30+6L \\\\\\ 12L-30=L^2-5L\implies 0=L^2-17L+30 \\\\\\ 0=(L-15)(L-2)\implies L= \begin{cases} \boxed{15}\\ 2 \end{cases}


now, we can't use L = 2, because, the whole job by both is done in 6 hours, there's no way the slower pump can do it in less than that, so L = 15.

now if L = 15, then L - 5 = 10.

5 0
4 years ago
Addison walked 6 miles in 4 hours what was her walking rate in hours per mile
Vlad [161]

Answer:

2/3 hour per mile.

Step-by-step explanation:

Hours per mile

= hours taken / miles walked

= 4/6 = 2/3 hour per mile.

5 0
3 years ago
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