Answer:
216 m
Explanation:
Assuming a straight line:
Δx = vt
Δx = (12 m/s) (18 s)
Δx = 216 m
Answer:
1. What was the diameter of the hailstone in inches_5.09_ and in cm___12.92___ and in feet ____0.42___?
2. What was the total volume of the hailstone in cubic inches___68.64___ and cubic feet____0.03____?
3. What was the fall velocity of this hailstone in m/s_____2.584____ and in mph___5.78_____?
Explanation:
1. If the circumference (L) of the stone is 16 inches, then from the following equation



1 inch = 2.54 cm = 0.08 ft, so 5.09 inches = 12..92 cm = 0.42 ft
2. The total volume is

3. The fall velocity is V = kd, where k = 20 if d is in cm. Let's calculate the fall velocity in cm.

2.584 m/s = 5.78 mph
Answer:
Making an observation.
Stating a question.
Formulating a hypothesis.
Conducting an experiment.
Analyzing the data and drawing conclusions.
Explanation:
Answer:
C) 50 m/s
Explanation:
With the given information we can calculate the acceleration using the force and mass of the box.
Newton's 2nd Law: F = ma
- 5 N = 1 kg * a
- a = 5 m/s²
List out known variables:
- v₀ = 0 m/s
- a = 5 m/s²
- v = ?
- Δx = 250 m
Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:
Substitute known values into the equation and solve for v.
- v² = (0)² + 2(5)(250)
- v² = 2500
- v = 50 m/s
The final velocity of the box is C) 50 m/s.