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stiv31 [10]
4 years ago
8

Please help me with my physics I don’t understand! Please provide work.

Physics
1 answer:
arsen [322]4 years ago
7 0
Ok I figured it out and hope it’s right
So the first object moving right at 5m/s
The second one moves left at 4m/s
If we multiply 2kg (5m/s) =10 kg/m/s
Same thing with the second one 1kg(4m/s)=4kg/m/s
We got two speeds and if we add them together we get 14 but I’m not sure about the units
So the answer would be A) 14m/s
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A cyclist has a constant speed of 12 m/s. What is the magnitude of the displacement of the cyclist after 18 seconds?
Katyanochek1 [597]

Answer:

216 m

Explanation:

Assuming a straight line:

Δx = vt

Δx = (12 m/s) (18 s)

Δx = 216 m

7 0
3 years ago
The 2nd largest hailstone every measured fell in Aurora, Nebraska, in 2003. The circumference of that hailstone was 16 inches. U
8_murik_8 [283]

Answer:

1. What was the diameter of the hailstone in inches_5.09_ and in cm___12.92___ and in feet ____0.42___?

2. What was the total volume of the hailstone in cubic inches___68.64___ and cubic feet____0.03____?

3. What was the fall velocity of this hailstone in m/s_____2.584____ and in mph___5.78_____?

Explanation:

1. If the circumference (L) of the stone is 16 inches, then from the following equation

L = 2\pi R

R = \frac{L}{2\pi} = \frac{16}{2\pi} = 2.54 ~inches

D = 2R = 5.09 ft

1 inch = 2.54 cm = 0.08 ft, so 5.09 inches = 12..92 cm = 0.42 ft

2. The total volume is

V = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi (2.54)^3 = 68.64~in^3\\68.64 ~in^3 = 0.03~ft^3

3. The fall velocity is V = kd, where k = 20 if d is in cm. Let's calculate the fall velocity in cm.

V = 20*12.92 = 258.4~cm/s = 2.584~m/s

2.584 m/s = 5.78 mph

4 0
3 years ago
Which components are part of all scientific investigations?
mezya [45]

Answer:

Making an observation.

Stating a question.

Formulating a hypothesis.

Conducting an experiment.

Analyzing the data and drawing conclusions.

Explanation:

6 0
3 years ago
An object with a momentum of 1600 kg m/s slows down and its new momentum is 900 kg m/s. What is the magnitude of the impulse tha
Anika [276]
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8 0
3 years ago
A 1kg box is pushed on a flat surface that is 250m long. The box is initially at rest and then pushed with a constant Net force
sasho [114]

Answer:

C) 50 m/s

Explanation:

With the given information we can calculate the acceleration using the force and mass of the box.

Newton's 2nd Law: F = ma

  • 5 N = 1 kg * a
  • a = 5 m/s²

List out known variables:

  • v₀ = 0 m/s
  • a = 5 m/s²
  • v = ?
  • Δx = 250 m

Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:

  • v² = v₀² + 2aΔx

Substitute known values into the equation and solve for v.

  • v² = (0)² + 2(5)(250)
  • v² = 2500
  • v = 50 m/s

The final velocity of the box is C) 50 m/s.

7 0
3 years ago
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