- Show that the equation d=vt2 dimensionally correct or not? ... nalsn7 is waiting for your help. Add your answer and earn points.
Answer:
Momentum change of the rock = 3835 kgm/s
Chane in earth's velocity = 6.4 x 10⁻²² m/s
Explanation:
m = 50.0 kg, M = 6.0 x 10²⁴ kg
d = 300.0 m
final velocity of rock = v, v² = 2gd = 2 * 9.81 * 300, so v = 76.7 m/s
Momentum change of the rock = mv = 50.0 * 76.7 = 3835 kgm/s
Inital momentum of the rock+earth system = 0
final momentum = 0 (momentum conservation)
momentum of rock and momentum of earth are same magnitude and opposite directions.
mv - MV = 0
Chane in earth's velocity = mv/M = 3835/(6.0 x 10²⁴) = 6.4 x 10⁻²² m/s
Answer:
3 : 08 : 10.9
Explanation:
assuming a 12 hour clock
angular velocity of the hour hand is 2π/(3600(12)) rad/s
angular velocity of the minute hand is 2π/3600 rad/s
difference is 2π/3600 - 2π/(3600(12)) = 11(2π/(3600(12)) rad/s
45° = π/4 radians
This angle is covered in a time of
π/4 rad / 22π / (3600(12)) = 900(12) / 22 = 490.909090... s
or about 8 minutes 10.9 s
ANSWER 3:08:10.9
Answer:
60 m
Explanation:
The boat has two separate motions:
1- A motion due north, with constant speed of 10 m/s
1- A motion due east, due to the current, at speed of 2 m/s
We know that the river is 300 m wide, so we can consider first motion 1) to find how much does it take for the boat to cross the river:

Now we can find how far downstream the boat moved by calculating the distance that the boat covered moving east during this time interval:

Answer:
238 cm3
Explanation:
You take the formula for volume, V = 2500.0 g/10.5 g/cm3 = 238.095 = 238 cm3. The answer is rounded to 3 significant figures.