1. Different ideas from different scientists (such as schleiden and schwann)
2. B. Describe and examine cells
3. Sorry i don't remember this
hope this helps :)
We can determine the empirical formula by first converting each of the grams to moles. remember to do this, first, we need the molar mass of the molecules which can be calculated by adding the mass of the atoms from the periodic table.
molar mass of CO2= 44.0 g/mol
molar mass of H2O= 18.02 g/mol
now, lets determine the grams of each atom
Carbon: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C
Hydrogen: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H
Oxygen: 10.0 - (6.54 + 0.55) = 2.91 g O
Now let's convert each mass to moles.
C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol
now that we have the moles of each atom, we need to divide them by the smallest value to find the ration. If you do not get the whole number, you need to multiply until to get a whole number.
C: 0.54 mol / 0.18 mol = 3
H: 0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1
empirical formula--> C₃H₃O
Answer:
It would take 13 minutes.
Explanation:
The temperature decreases at a linear rate, meaning that we can describe the process by using the following formula:
Where T₂ is the final temperature, T₀ is the initial temperature; and t is the elapsed time in minutes.
We input the data given by the problem:
- 0 °C = 26 °C - 2°C/min * t
And solve for t:
Answer:
Organisms
Step-by-step explanation:
Properties of Life. All living organisms share several key characteristics or functions: order, sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.
When a covalent bond<span> is present between two </span>atoms<span>, the </span>covalent radius<span> can be determined. When two </span>atoms<span> of the same </span>element<span> are covalently </span>bonded<span>, the </span>radius<span> of each </span>atom<span> will be half the distance between the two nuclei because they equally attract the electrons.</span>
