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jeyben [28]
2 years ago
10

What can I do a sentence with frost wedging

Chemistry
1 answer:
jok3333 [9.3K]2 years ago
3 0

ok, here is a sentence for you:

Frost wedging is a process that is an occurrence when ice forms in a tiny crack of a rock and then i breaks slowly melting away and eroding the surface of the rock or mineral etc.

I hope this helps you!

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6.3 kJ of energy is required to increase the temperature of some water from 60 °C to 75 °C. The specific heat capacity of water
Andreas93 [3]

Answer:

Mass of the water = 0.1kg is 100g

Explanation:

Mathematically;

Quantity of heat = mass of water * specific heat capacity * temperature change

From the question, we identify the following;

Quantity of heat = 6.3 KJ

1 KJ = 1000 J, so 6.3 KJ = 6.3 * 1000 = 6300 J

Mass of water = ?

Specific heat capacity = 4200

Temperature change is the difference between the final and initial temperature. = 75-60 = 15

6300 = m * 15 * 4200

63 = m * 15 * 42

63 = 630 m

m = 63/630

m = 0.1 kg

4 0
3 years ago
What are air pollutants
KIM [24]

Answer:

things that pollute the air

Explanation:

nuclear energy, fossil fuels, gas from cars and other transportation, and these all contribute to greenhouse gases that are harmful to the environment

hope this helped!

5 0
2 years ago
Reading the temperature of a solution by using a thermometer is an example of a(n) ________.
weeeeeb [17]

Answer:

i guess its example of observation

6 0
2 years ago
Newton’s second law of motion is F=ma A net force of 60 N north acts on an object with a of 30 kg. Use Newton’s second law of mo
horsena [70]
I’m pretty sure the immediate answer is 2. Using the equation 60N=(30kg)x2(whatever unit of measure) also it will change because if you change the mass or the Net Force, your going to have to redo the equation based on the new information.
8 0
3 years ago
Read 2 more answers
A sample of calcium phosphate was found to have a mass of 125.3 g. How many molecules were contained in the sample?
Viktor [21]

The answer for the following problem is mentioned below.

  • <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules.</em></u>

Explanation:

Given:

mass of calcium phosphate (Ca_{3}(PO_{4} )_{2} ) = 125.3 grams

We know;

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = (40×3) + 3 (31 +(4×16))

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = 120 + 3(95)

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} )  = 120 +285 = 405 grams

<em>We also know;</em>

No of molecules at STP conditions(N_{A}) = 6.023 × 10^23 molecules

To solve:

no of molecules present in the sample(N)

We know;

\frac{m}{M} =\frac{N} }{}N÷N_{A}

\frac{405}{125.3} =\frac{N}{6.023*10^23}

N =(405×6.023 × 10^23) ÷ 125.3

N = 19.3 × 10^23 molecules

<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules</em></u>

3 0
3 years ago
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