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2 years ago

NHCI(s) = NH3(g) + HCl(g) at 427°C, Kp = 4.8. Calculate Kc

Chemistry

1 answer:

eduard2 years ago

7 0

$\tt Kp=Kc(RT)^{\Delta n}$

NH₄Cl (s) ⇔ NH₃ (g) + HCl (g)

Δn = 2 (gas only)

R = 0.082

T = 427 + 273 = 700 K

4.8 = Kc (0.082 x 700)²

Kc = 1.45 x 10⁻³

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NHCI(s) = NH3(g) + HCl(g) at 427°C, Kp = 4.8. Calculate Kc​

NHCI(s) = NH3(g) + HCl(g) at 427°C, Kp = 4.8. Calculate Kc