Magnesium bromide= MgBr2
Potassium chloride= KCl
Answer:
B. the products have a smaller number of available energy microstates than the reactants.
Answer:
It's Effective Collision.
Explanation:
Hope my answer has helped you!
<span>2.28 kg x 213 kJ/kg = 486 kJ = 4.86E+05 J</span>
Hi!
The correct option would be 3.85x10^(24)
To find the number of atoms in 250g of potassium, we need to first calculate the number of atoms in
1 mole of Potassium = 39g which contains 6.022x10^(23) atoms of K
<em>(Avogadro's constant value for the amount of molecules/atoms in one mole of any substance)</em>
<em>Solution</em>
So as 39g of Potassium contains 6.022x10^(23) K atoms
1g of Potassium would contain 6.022x10^(23) / 39 = 1.544 x10^(22) atoms
So 250g of Potassium would contain 1.544x10^(22) x 250 = 3.86x10^(24) atoms
