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cluponka [151]
2 years ago
8

Pls help! Fill in the blanks.

Physics
1 answer:
mart [117]2 years ago
5 0

Answer:

attracting iron and producing a magnetic field

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If $1,800 is invested in a savings account offering interest at a rate of 4.5% per year, compounded continuously, how fast is th
Archy [21]

Answer:

The total amount  after 3 years is = $ 2054.10

Explanation:

Given data

Principal Amount (P) = $ 1800

Rate of interest (R) = 4.5 %

Thus the total amount after 3 years compounded annually is given by the formula =  P × [1 +\frac{R}{100}  ]^{3}

⇒ 1800 × [1 +\frac{4.5}{100}  ]^{3}

⇒ 2054.10

Thus the total amount  after 3 years is = $ 2054.10

Compound interest earned in three years = 2054.10 - 1800 = $ 254.10

3 0
3 years ago
Bro i need help omg.
sergey [27]

Answer:

25.

Explanation:

8 0
2 years ago
Read 2 more answers
Earth’s polar ice caps contain about 2.3 × 1019 kg of ice. This mass contributes essentially nothing to the moment of inertia of
sp2606 [1]

Answer:

Explanation:

Initial moment of inertia of the earth I₁ = 2/5 MR² , M is mss of the earth and R is the radius . If ice melts , it forms an equivalent shell of mass  2.3 x 10¹⁹ Kg

Final moment of inertia I₂ = 2/5 M R² + 2/3  x 2.3 x 10¹⁹ x R²

For change in period of rotation we shall apply conservation of angular momentum law

I₁ ω₁  = I₂ ω₂  ,  ω₁ and   ω₂ are angular velocities initially and finally .

I₁ / I₂     =  ω₂ / ω₁

I₁ / I₂     =  T₁ / T₂  , T₁ , T₂ are time period initially and finally .

T₂ / T₁ = I₂ / I₁

(2/5 M R² + 2/3  x 2.3 x 10¹⁹ x R²) / 2/5 MR²

1 + 5 / 3  x 2.3 x 10¹⁹ / M

= 1 + 5 / 3  x 2.3 x 10¹⁹ / 5.97 x 10²⁴

= 1 + .0000064

T₂ = 24 (1 + .0000064)

= 24 hours + .55 s

change in length of the day = .55 s .

3 0
2 years ago
An 8.00- W resistor is dissipating 100 watts. What are the current through it and the difference of potential across it?
hjlf

Answer:

I= 3.5 amps

Explanation:

Step one:

given data

rating of resistor R= 8 ohms

power P= 100W

Required

The current I

Step two

Yet this power is also given by

P = I^2R

make I subject of the formula we have

I= \sqrt{\frac{P}{R} }

substitute

I= \sqrt{\frac{100}{8} }\\\\I=\sqrt{12.5}\\\\I= 3.5 amps

8 0
3 years ago
Suppose for your cookout you need to make 100 hamburgers. You know that 2.00 pounds will make 9 hamburgers. How many pounds will
VMariaS [17]
2 pounds = 9 burgers figure out ow many 9's you can get out of 100: 100/9=11 but that only makes 99 you need 100 so we would add another one making 12. now multiply 12 by 2: 12·2=24. You would need 24 pounds of meet :)

8 0
3 years ago
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