Answer:
is his final displacement from the point A after 60 seconds.
Explanation:
Given:
Cyclist is moving away from A.
- velocity of cyclist,

- displacement of the cyclist from point A at the time of observation,

- time after which the next observation is to be recorded,

Now as the cyclist is moving away from point A his change in displacement after the mentioned time:



<u>Now the the final displacement from point A after the mentioned time:</u>



Explanation:
I'm corona positive and isolated feeling depressed just logged in to talk someone but people ignoring me thanks for this behaviour got disappointed bye everyone logging out had a great time
Answer:
This is as a result that about the central axis a collapsed hollow cone is equivalent to a uniform disc
Explanation:
The integration of the differential mass of the hollow right circular cone yields

and for a uniform disc
I = 1/2πρtr⁴ = 1/2Mr².
Explanation:
The liquid contains only one element. -The liquid is a pure substance. The number at the end of an isotope's name is the -mass number. While looking at xenon (Xe) on the periodic table, a student needs to find an element with a smaller atomic mass in the same group.