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3 years ago

In science, does acceleration happen when an object is slowing down?

Physics

1 answer:

Irina18 [472]3 years ago

7 0

Answer:

According to our principle, when an object is slowing down, the acceleration is in the opposite direction as the velocity. Thus, this object has a negative acceleration. In Example D, the object is moving in the negative direction (i.e., has a negative velocity) and is speeding up.

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What is the longest wavelength of radiation that possesses the necessary energy to break the bond 941?

Anna71 [15]

<span>Energy is calculated by molecule dividing energy by mole by Avogadro's number (6.022*10^23) 941kJ=9.41*10^5 J so energy by molecule E= 9.41*10^5/6.022*10^23=1.563*10^-18 J Wavelength (w) given by E=hc/w where, E = energy h = planks constant (6.6262 x 10-34 JÂ·s) c = speed of light (3 x 10^8 m/s ) So, w= hc/E = (6.6262*10^-34)*(3*10^8) /1.563*10^-18 = 127.2 Nm Longest wavelength of radiation =127.2 Nm</span>

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3 years ago

What is Intracellular communication

Komok [63]

Answer:

Intercellular communication refers to the communication between cells. Membrane vesicle trafficking has an important role in intercellular communications in humans and animals, e.g., in synaptic transmission, hormone secretion via vesicular exocytosis.

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3 years ago

If 478 watts of power are used in 14 seconds,how much work was done

zepelin [54]

Answer:

6692J

Explanation:

Power is defined as the rate at which work is being done.

So,

Power = $\frac{workdone}{time }$

Work done = Power x time

Given parameters:

Power = 478watts

Time = 14s

So;

Work done = 478 x 14 = 6692J

6 0

3 years ago

How to indicate kinetic energy

QveST [7]

Answer:

its moving

Explanation:

8 0

3 years ago

A free falling object has the velocity time graph shown. What is the objects displacement between 0.0 and 6.0s

zloy xaker [14]

For free fall motion the displacement can be found by graphically as well as by kinematics equation

Here acceleration of object is constant as it fall due to gravity so we can use

$d = v_i * t + \frac{1}{2}at^2$

here if body starts with zero initial speed then we can say

$d = 0 + \frac{1}{2}*9.8*t^2$

here we need to find the displacement from t = 0 to t = 6s

so we can say

$d = \frac{1}{2}*9.8*6^2$

$d = 176.4 m$

so the displacement will be 176.4 m

in order to find the displacement from the graph of velocity and time we need to find the area under the graph for given time interval that will also give us same displacement for given period of time.

6 0

4 years ago

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