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3 years ago

10

On the visible satellite image, the sun’s rays would be reaching earth generally from the

1 answer:

patriot [66]3 years ago

8 0

<span>Visible satellite images are like photos which are dependent on visible light from the sun so they work best during the day. The sensor works by detecting radiation within the range that wavelength is visible. Because of this, the rays is usually seen as reaching earth from the East. </span>

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How much potential energy does a 40n block medicine ball gain when it is lifted 5.m

MAVERICK [17]

By definition, the gain in PE (potential energy) is
ΔPE = m*g*h

Given:
mg = 40 N (Note that m*g = weight)
h = 5 m

ΔPE = (40 N)*(5 m) =200 J

Answer: 200 J

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3 years ago

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a cruise ship travels directly toward the dock with a velocity of 15 m/s relative to the water. A passenger walks 3 m/s in the s

solong [7]

Answer:

Explanation:

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3 years ago

Which statement best describes the relationship between an object's density and its index of refraction? as the optical density

babunello [35]

For future references, the answer is B.

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A 40-kg box is being pushed along a horizontal smooth surface. The pushing force is 15 n directed at an angle of 15Â° below the

Kobotan [32]

Answer:

Acceleration of the crate is 0.362 m/s^2.

Explanation:

Given:

Mass of the box, m = 40 kg

Applied force, F = 15 N

Angle at which the force is applied, $(\theta)$ = 15°

We have to find the magnitude of the acceleration.

Let the acceleration be "a".

FBD is attached with where we can see the horizontal and vertical component of force.

⇒ $F_x=Fcos(\theta)$ and ⇒ $F_y=Fsin (\theta)$

⇒ $F_x=15cos(15)$ ⇒ $F_y=15sin (15)$

⇒ Applying concept of forces.

⇒ $\sum F_x=F_n_e_t =F-f$

⇒ $F_n_e_t =F-f$

⇒ $ma =F-f$ <em> ...Newtons second law Fnet = ma</em>

⇒ $a =\frac{F-f}{m}$

⇒ Plugging the values.

⇒ $a =\frac{15cos(15)-0}{40}$ <em>...f is the friction which is zero here.</em>

⇒ $a =\frac{14.48}{40}$

⇒ $a=0.362\ ms^-^2$

Magnitude of the acceleration of the crate is 0.362 m/s^2.

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3 years ago

If 11,550 J heat is absorbed by a copper object when it is heated from 20.0°C to 30.0°C,

RSB [31]

Answer:

The mass of the copper is 3.00kg

Explanation:

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3 years ago