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2 years ago

How do longshore currents shape the land?

2 answers:

5 0

Longshore drift has a very powerful influence on the shape and composition of the coastline. It changes the slopes of beaches and creates long, narrow shoals of land called spits, that extend out from shore. Longshore drift may also create or destroy entire “barrier islands” along a shoreline.

Llana [10]2 years ago

4 0

Answer:

You might be interested in

At a certain location, Earth has a magnetic field of 0.60 â 10â4 T, pointing 75Â° below the horizontal in a north-south plane. A

krek1111 [17]

Answer:

a) $= 9.30\times 10^{-3} N$

b) $= 2.49\times 10^{-3} N$

Explanation:

Given data;

magnetic field $= 0.60 \times 10^{-4} T$

current I = 11 A

length of wire L = 14.6 m

Angle $\theta = 75 A$

a) Magnetic force due to current

$F = BIL sin \theta$

$= 0.60 \times 10^{-4} \times 11 \times 14.6 sin 75^o$

$= 9.30\times 10^{-3} N$

B) magnitude of force due upward current direction

$F = BIL sin \theta$

$= 0.60 \times 10^{-4} \times 11 \times 14.6 sin (75^o + 90^o)$

$= 2.49\times 10^{-3} N$

4 0

3 years ago

An airplane with a speed of 92.3 m/s is climbing upward at an angle of 51.1 ° with respect to the horizontal. When the plane's a

devlian [24]

Answer:

$D = 1162.7 \ m$

$\beta =- 65.55^o$

Explanation:

From the question we are told that

The speed of the airplane is $u = 92.3 \ m/s$

The angle is $\theta = 51.1^o$

The altitude of the plane is $d = 532 \ m$

Generally the y-component of the airplanes velocity is

$u_y = v * sin (\theta )$

=> $u_y = 92.3 * sin ( 51.1 )$

=> $u_y = 71.83 \ m/s$

Generally the displacement traveled by the package in the vertical direction is

$d = (u_y)t + \frac{1}{2}(-g)t^2$

=> $-532 = 71.83 t + \frac{1}{2}(-9.8)t^2$

Here the negative sign for the distance show that the direction is along the negative y-axis

=> $4.9t^2 - 71.83t - 532 = 0$

Solving this using quadratic formula we obtain that

$t = 20.06 \ s$

Generally the x-component of the velocity is

$u_x = u * cos (\theta)$

=> $u_x = 92.3 * cos (51.1)$

=> $u_x = 57.96 \ m/s$

Generally the distance travel in the horizontal direction is

$D = u_x * t$

=> $D = 57.96 * 20.06$

=> $D = 1162.7 \ m$

Generally the angle of the velocity vector relative to the ground is mathematically represented as

$\beta = tan ^{-1}[\frac{v_y}{v_x } ]$

Here $v_y$ is the final velocity of the package along the vertical axis and this is mathematically represented as

$v_y = u_y - gt$

=> $v_y = 71.83 - 9.8 * 20.06$

=> $v_y = -130.05 \ m/s$

and v_x is the final velocity of the package which is equivalent to the initial velocity $u_x$

$\beta = tan ^{-1}[-130.05}{57.96 } ]$

$\beta =- 65.55^o$

The negative direction show that it is moving towards the south east direction

6 0

3 years ago

Johannes Kepler, an apprentice of Brahe, believed in the heliocentric universe but rejected past astronomers' belief in

Rashid [163]

<span>So the question is in what did johannes Kepler reject since he believed in the heliocentric universe. So heliocentric system is a system where the sun is in the center of the Solar system. Geocentric system is the system where Earth, not Sun is in the center of our system. He was against Geocentric system. </span>

5 0

3 years ago

Read 2 more answers

a car that is moving in a straight line has an acceleration of 8.0 m/s/s for 4.0 seconds. which one of the following is true of

Nuetrik [128]

Answer:

32 ms

Explanation:

v=32ms.

Explanation:

I will assume that you mean that the acceleration is 8.0 ms2, as 8.0ms is a value for velocity, not acceleration.

Here, we use the formula v=u+at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is time. Let's substitute values, then:

v=u+at,

v=0+8.0⋅4.0

v=32,

v=32ms.

Hope it Helps! :D .

7 0

2 years ago

What type of energy does the horse have because of its motion?

Alekssandra [29.7K]

is the horse running/moving? if so then kinetic i believe

7 0

2 years ago