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2 years ago

Ellus

Physics

1 answer:

Lesechka [4]2 years ago

6 0

Answer:

W'=125.44 N

Explanation:

The weight of a person on the surface of Earth is 784 N

Weight is given by :

W = mg

m is mass of the person and g is acceleration due to gravity on the surface of Earth (10 m/s²)

$m=\dfrac{W}{g}\\\\m=\dfrac{784}{10}\\\\m=78.4\ kg$

The acceleration due to gravity on the surface of Moon, g' = 1.6 m/s²

Weight of the person on the moon is :

W'=mg'

$W'=78.4\ kg\times 1.6\ m/s^2\\\\W'=125.44\ N$

Hence, the person would weigh 125.44 N on the Moon.

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What is the momentum of a 5 kg object that has a velocity of 1.2 m/s? 3.8 kg • m/s 4.2 kg • m/s 6.0 kg • m/s 6.2 kg • m/s

Gnesinka [82]

Answer:

Your answer will be 6.0kg•m/s

Explanation:

In the given question all the required details d given. Using these information's a person can easily find the momentum of the object. In the question it is already given that the mass of the object is 5 kg and the velocity at which it is traveling is 1.2 m/s.We know the equation of finding momentum asMomentum = mass * velocity = 5 * 1.2 = 6So the momentum of the object is 6 Newton.

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3 years ago

Read 2 more answers

What acceleration will you give to a 24.5 kg

Ludmilka [50]

Heya!!

For calculate aceleration, lets applicate second law of Newton:

$\boxed{F=ma}$

Δ Being Δ

F = Force = 78,3 N

m = Mass = 24,5 kg

a = Aceleration = ?

⇒ Let's replace according the formula and clear "a":

$\boxed{a=78,3\ N / 24,5\ kg}$

⇒ Resolving

$\boxed{a=3.19\ m/s^{2}}$

Result:

The aceleration is 3,19 meters per second squared (m/s²)

Good Luck!!

4 0

3 years ago

What will happen if a car experiences a 300 N force to the right from the engine and a separate 150 N force due to friction and

gayaneshka [121]

Force applied on the car due to engine is given as

$F_1 = 300 N$ towards right

Also there is a force on the car towards left due to air drag

$F_2 = 150 N$ towards left

now the net force on the car will be given as

$\vec F_{net} = \vec F_1 + \vec F_2$

now we can say that since the two forces are here opposite in direction so here the vector sum of two forces will be the algebraic difference of the two forces.

So we can say

$F_{net} = F_1 - F_2$

$F_{net} = 300 - 150$

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3 years ago

I need help with this

fredd [130]

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Using the relation:

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And then we can turn take the inverse to get the effective resistance.

Where r is the magnitude of the resistance offered by each resistor.

In this case we have,
(every term has an mho in the end)
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we get,
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The potential difference is of 9V.

So the current flowing using ohm's law,

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2 years ago

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levacccp [35]

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