As weight =w =mg
g= gravitational acceleration on mercury = 3.7m/sec2
Mass of person =m= 70 kg
So w =(70kg)(3.7m/sec2)
w= 259 kgm/sec2
W= 259 N
The complementary base pair is:
TTC, CTG, AGT, CTA.
-- The student's distance traveled is 200 meters.
-- The student's displacement is 141 meters Northeast.
A b c d e f g h i j k l m
C. is the answer to this question