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Murrr4er [49]
2 years ago
10

Chemistry question, 20 points, will mark as brainliest if correct:

Chemistry
1 answer:
Brums [2.3K]2 years ago
3 0

Answer:

CS2 + 3O2 -> CO2 + 2SO2

Explanation:

You might be interested in
Hydrogen cyanide, HCN, can be made by a two-step process. First, ammonia reacts with O2 to give nitric oxide, NO.
stealth61 [152]

Answer:

The mass of HCN is 79.65 g.

The mass of reactant which remain at the end of both reactions is 88.5 g.

Explanation:

Given that,

Mass of ammonia = 50.2 g

Mass of methane = 48.4 g

Hydrogen cyanide, HCN, can be made by a two-step process

Ammonia reacts with O₂ to give nitric oxide NO.

The reaction is,

4NH_{3}+5O_{2}\Rightarrow 4NO+6H_{2}O

We need to calculate the mole of NO

Using given data,

2.25 g NH_{3}=\dfrac{50.2}{17}= 2.95\ mole\ NH_{3} [/tex]

4\ mole NH_{3}\ glose 4\ mol NO

2.95 mol NH₃ will produced 2.95 mol NO

Then nitric oxide reacts with methane,

The reaction is,

2NO+2CH_{4}\Rightarrow 2HCN+2H_{2}O+H_{2}

We need to calculate the mole of methane

Using given data,

mole\ of\ methane=\dfrac{48.4}{16}

mole\ of\ methane = 3.03\ moles

2 mole NO produced 2 mole HCN

2.95 mol NO will produced \dfrac{2.95\times3.03}{3.03}= 2.95 mol HCN

We need to calculate the mass of HCN

Using formula of mass

m=N\times M

Where, N = number of mole

M = molecular mass

Put the value into the formula

m=2.95\times27

m= 79.65\ g

The mass of HCN is 79.65 g.

We need to calculate the mass of NO

Using formula of mass

m=N\times M

Where, N = number of mole

M = molecular mass

Put the value into the formula

m=2.95\times30

m= 88.5\ g

Hence, The mass of HCN is 79.65 g.

The mass of reactant which remain at the end of both reactions is 88.5 g.

4 0
4 years ago
If I started with 42.00 L of oxygen (O2) gas, how many grams is that?
belka [17]

Answer:

42 liters of oxygen (liquid) weighs 47900 grams.

Explanation:

5 0
3 years ago
Which coefficients correctly balance the formula equation nh4no2(s)-> n2(g) + h2o(l)?
horrorfan [7]
NH4NO2 > N2 + 2 H2O
8 0
3 years ago
A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?
viva [34]
<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

 = 0.140 moles × 74.5 g/mole

 = 10.43 g

Concentration in g/L

   = mass in g/volume in L

   = 10.43/2.1

   =  4.9667

<h3>   <u> ≈ 4.95 g/L</u></h3>
4 0
4 years ago
The incomplete table below shows selected properties of compounds that have ionic, covalent, or metallic bonds.
pogonyaev

Answer:

is there an option for silver? if so, silver is the answer.

8 0
2 years ago
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