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Law Incorporation [45]
3 years ago
12

Suppose you have a dozen carbon atoms, a dozen gold atoms, and a dozen iron atoms. Even though you have the same number of each,

would you expect them all to have the same mass? Explain.
Chemistry
2 answers:
Amanda [17]3 years ago
8 0

Answer:

NO!

Explanation:

Not considering isotopes for the moment.  All the atoms of any one element have the same mass.   From the periodic table,  and using whole numbers, you may note that the mass of one atom of hydrogen is one atomic mass unit (amu) and the mass of one carbon atom is 12 amu

So, the one carbon (C) atom is 12 times more massive than one hydrogen (H) atom

If you have the same number or each  the carbon atoms will always be 12 times more massive.

The fundamental, concept, is that (again neglecting isotopes) since all the atoms of any one element are the same, we count out atoms by massing the atoms.   We choose to measure masses in grams, and the counting units is the mole--a number.   Like we count out eggs by the number 12, which we call a dozen,   we count out atoms by the number mole which is a huge, huge number 6.02  x 10 to the 23rd power.  

To comprehend how large the number mole is, I had various students count out a mole of atoms or a mole of molecules by massing them, and then each brought the mole of what they had into a gym which measured 100ft by 100ft.  

The question then became, if you had a mole of raindrops, average diameter 0,04cm, how high would the gym walls have to be to hold the mole of raindrops, assuming no compressing of the water molecules.

The answer is nearly 1,000 times the distance between the earth and the moon.   The reaction is WOW, they must be so small,   YEP!

They got extra credit if they could come up with another accurate and fun way of describing the number mole.

mixer [17]3 years ago
3 0

Answer:

By weight they have the same mass, but the number of atoms is different

Explanation:

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The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


3 0
3 years ago
¿Cómo se escribe la fórmula molecular (orden de los iones)?
cluponka [151]

Answer:

A la izquierda el catión y a la derecha el anión.

Explanation:

¡Hola!

En este caso, y basado en las normas IUPAC para la escritura de las fórmulas moleculares, es necesario primero escribir el catión a la izquerda, seguido del anión a la derecha, tal y como se muestra en los siguientes ejemplos, recordando que el catión es el ion cargado positivamente y el anión, negativamente:

K^+Cl^-\\\\Ag_2^+(SO_4)^{2-}

Los cuales son cloruro de potasio y sulfato de plata respectivamente. También es necesario tener en cuenta que los metales tienden a ser cationes por su capacidad de perder electrones, mientras que los no metales a ganarlos y por ende resultar como aniones.

¡Un gusto ayudarte!

6 0
3 years ago
How do different bridge designs react to stong winds
anastassius [24]

Depending on how the design is, The bridge will sway, bounce, or move in some way. If the bridge was too stiff the winds would destroy the bridge and cause it to crumble and fall.

Hope that answer works for you! :)

3 0
3 years ago
Rosa was looking for patterns to help predict the products of chemical reactions. She recorded three similar decomposition react
Luda [366]

Answer:

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Explanation:

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3 years ago
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A piece of magnesium is in the shape of a cylinder with a height of 6.62 cm and a diameter of 2.34 cm. If the magnesium sample h
frez [133]

Answer:

0.600 g/cm³

Explanation:

Step 1: Given data

  • Height of the cylinder (h): 6.62 cm
  • Diameter of the cylinder (d): 2.34 cm
  • Mass of the cylinder (m): 17.1 g

Step 2: Calculate the volume of the cylinder

First, we have to determine the radius, which is half of the diameter.

r = d/2 = 2.34 cm/2 = 1.17 cm

Then, we use the formula for the volume of the cylinder.

V= π × r² × h

V= π × (1.17 cm)² × 6.62 cm

V = 28.5 cm³

Step 3: Calculate the density (ρ) of the sample

The density is equal to the mass divided by the volume.

ρ = m/V

ρ = 17.1 g/28.5 cm³

ρ = 0.600 g/cm³

8 0
2 years ago
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