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PolarNik [594]
4 years ago
10

One way that scientists ensure that data are reliable is through

Chemistry
1 answer:
Vesna [10]4 years ago
4 0
Replicating experiments

(If u don’t mind can y mark me brainiest it would really help :) )
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In your own words, explain why the Linnaean system has changed over time pls help
sergiy2304 [10]

Classification systems are mental models that we create to make sorting things simpler and more efficient. We make compromises to emphasize certain details and hide others based on their perceived relevance to achieving the outcomes we seek. Even if the original model was nearly perfect, you should expect the inputs provided and outcomes desired to change as time goes by.

In time, we usually find that we have over-simplified by ignoring important details. Mental models such as classification systems should evolve over time. This enables them to more accurately reflect reality and lead to the outcomes we seek.

You can only find the details you seek by observing the right layer of abstraction.

8 0
3 years ago
Which of the following would be a qualitative observation? A The volume of the solution is 25 ml B The solution turned blue C Th
mariarad [96]
B

A qualitative observation describes the characteristics of a substance without quantifying them.
3 0
4 years ago
What you all are doing?​
earnstyle [38]

Answer:playing

Explanation:

8 0
2 years ago
Read 2 more answers
What is the mass in grams of 17.46 mL m L of acetone?
Crazy boy [7]

Answer:

17,46gram

Explanation:

because 1l is egal to kg

4 0
3 years ago
Read 2 more answers
The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

8 0
3 years ago
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