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Mademuasel [1]
3 years ago
7

What is the area of triangle 12cmx12cmx8cmx14cm

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
4 0
The Answer is 16,128 cm
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Photo math is charging?   We don't need it.  We factor the difference of two squares.

\dfrac{5t^2-500}{t+10} = \dfrac{5(t^2- 100)}{t+10} = \dfrac{5(t-10)(t+10)}{t+10} = 5(t-10) = 5t-50

Answer: 5t-50

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4 years ago
There are 3 different highways from City W to
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6 x 4 you have 4 numbers and each can be put in 6 different ways. so it is 24 i think

Step-by-step explanation:

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The base parking charge at a mall on a Sunday is $2 per hour. If a vehicle is parked for 4 hours, only $6 is charged. What perce
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a weather forecast predicts a 30% chance of rain for each of the next three days. describe a way to simulate the chance that it
topjm [15]

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Draw a pie chart looking wheel with 30% and 70% and spin the wheel three times and see what it lands on each time

Step-by-step explanation:

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3 years ago
Please help me out :P
Veseljchak [2.6K]

cos θ = \frac{-4\sqrt{65} }{65}, sin θ = \frac{-7\sqrt{65} }{65}, cot  θ  = 4/7, sec  θ = \frac{-\sqrt{65} }{4}, cosec  θ  = \frac{-\sqrt{65} }{7}

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = \sqrt{7^{2} + 4^{2} } = \sqrt{49+16} = \sqrt{65}

sin θ = opposite/ hyp = \frac{7}{\sqrt{65} }

Rationalize, \frac{7}{\sqrt{65} } x \frac{\sqrt{65} }{\sqrt{65} } = \frac{7\sqrt{65} }{65}

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - \frac{7\sqrt{65} }{65}

cos   θ  = adj/hyp = \frac{4}{\sqrt{65} }

By rationalizing and knowing that cos  θ  is negative, cos θ  = -\frac{-4\sqrt{65} }{65}

cot θ  = 1/tan θ  = 1/7/4 = 4/7

sec θ  = 1/cos θ  = 1/\frac{4}{\sqrt{65} } = -\frac{-\sqrt{65} }{4}

cosec θ  = 1/sin θ  = 1/\frac{\sqrt{65} }{7} = \frac{-\sqrt{65} }{7}

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0
2 years ago
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