2. Atoms of the element beryllium would most likely behave similar to the way _______ behaves.
2 answers:
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Answer:
The concentration of KOH is 0.186 M
Explanation:
First things first, we need too write out the balanced equation between HBr and KOH.
This is given as;
KOH (aq) + HBr (aq) → KBr (aq) + H2O (l)
From the reaction above, we can tell that it takes 1 mole of KOH to react with 1 mole of HBr.
We use the acid base formular in calculating unknown concentrations. This is given as;
where;
Ca = Concentration of acid
Va = Volume of acid
Cb = Concentration of base
Vb = Volume of base
na = Number of moles of acid
nb = Number of moles of base
KOH is the base and HBr is acid.
Hence;
Ca = 0.225
Va = 35
Cb = ?
Vb = 42.3
na = 1
nb = 1
Making Cb subject of formular we have;
Cb = (0.225 * 35 * 1) / (42.3 * 1)
Cb = 0.186 M
The balanced chemical equation representing the process of photosynthesis is:
The reactants in the process of photosynthesis are and H
and the products of the reaction are glucose
and oxygen
. Oxygen is the nonpolar covalent gas which is released in the process of photosynthesis. The reactant
is a nonpolar covalent gas while the other reactant water
has polar covalent O-H bonds.
In the balanced chemical equation, the number of each type of element must be equal on both sides of the reaction.