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4 years ago

What does your data indicate about the optimum ph level for this enzyme-catalyzed reaction?

1 answer:

3 0

At an optimum pH of 7.0, there are more molecules per minute in all amounts of substrate thus this pH is ideal for maximum growth. 5. Enzymes function most efficiently at the temperature of a typical cell, which is 37 degrees Celsius. Increases or decreases in temperature can significantly lower the reaction rate.

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Please answer!! I’ll make brainliest!!

Alenkinab [10]

Answer:

greater than 115 N upwards

Explanation:

3 0

3 years ago

One way to heat a gas is to compress it. a gas at 1.00 atm at 25.0°c is compressed to one tenth of its original volume, and it r

Tanzania [10]

(p1)(V1)/(T1) = (p2)(V2)/(T2)
(1.00 atm)(V) / (273 + 25K) = (40.0 atm)(V/10) / (273 + T)
273 + T = (40.0)(1/10)(273 + 25K) / (1.00)
T = 919°C

5 0

3 years ago

Given the following balanced equation, determine the rate of reaction with respect to [SO2].

Gnoma [55]

Answer:

Rate = -1/2 Δ[SO<sub>2</sub>]/Δt

so its gonna be (in more simple terms) rate= -1/2Δ(SO2)/Δt

Explanation:

7 0

3 years ago

What mass in grams would 5.7L of hydrogen gas occupy at STP?

tekilochka [14]

Answer: The correct answer is: " 0.54 g " .

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Explanation:

Note that "hydrogen gas" is:

H₂ (g) ; that is: a "diatomic element" (diatomic gas) ;

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The molecular weight of "H" is: 1.00794 g ;

(From the Periodic Table of Elements).

So, the molecular weight of: H₂ (g) is:

" 1.00794 g * 2 = 2.01588 g ; {use calculator) ;

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Note the conversion for a gas at STP:

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1 mol of a gas = 22.4 L gas;

___

i.e. " 1 mol / 22.4 L " ;

____

So: " 5.7 L H₂ (g) $* \frac{1 mol H_{2} }{22.4 L} *\frac{2.01588 g}{mol} =? ;$

The "L" ("literes" cancel out to "1" ; since "L/L = 1 ;

The "mol" (moles) cancel out to "1" ; since "mol/mol = 1 ;

____

and we are left with:

____

[5.7 * 2.104588 g ] / 22.4 = ? g ;

______________________

→ [ 11.9961516 g ] / 22.4 =

0.53554248214 g ;l

_____________________________

We round this value to: " 0.54 g " ;

→ since "5.7 L " has 2 (two) significant figures;

22.4 is an exact number conversion;

and "5.7 L" has fewer significant figures than:

" 2.104588 " ; or: " 1.00794 " .

→ as such: We round to "2 (two) significant figures."

______________________________

Hope this is helpful. Wishing you the best in your academic endeavors!

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8 0

3 years ago

Calculate the molarity of a solution of sodium hydroxide, naoh, if 23.64 ml of this solution is needed to neutralize 0.5632 g of

GuDViN [60]

The molarity of NaOH needed is calculated as follows
calculate the moles of KhC8h4O4

that is moles = mass/molar mass of KhC8h4O4(204.22 g/mol)

=0.5632g /204.22g/mol= 2.76 x10^-3 moles

write the equation for reaction

khc8h4O4 + NaOH ---> KNaC8h4O4 + H2O

from the equation above the reacting ratio of KhC8h4O4 to NaOh is 1:1 therefore the moles of Naoh is also 2.76 x10^-3 moles

molarity of NaOh = (moles of NaOh / volume ) x 1000

that is { (2.76 x10^-3) / 23.64} x100 =0.117 M

8 0

3 years ago