What does your data indicate about the optimum ph level for this enzyme-catalyzed reaction?
1 answer:
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Answer:
The percentage efficiency of the electrical element is approximately 82.186%
Explanation:
The given parameters are;
The thermal energy provided by the stove element, = 3.34 × 10³ J
The amount thermal energy gained by the kettle, = 5.95 × 10² J
The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;
Therefore, we get;
The percentage efficiency of the electrical element, η% ≈ 82.186%.