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malfutka [58]
3 years ago
9

How can a mixture of sand and water be separated? chromatography magnetic attraction filtration crystallization

Chemistry
1 answer:
atroni [7]3 years ago
4 0
It would be C) filtration. Hope this helps.
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If 190dm of hydrogen gas collected at 20°c and 760mmHg .Calculate it's volume at stp (standard pressure=760mmHg
Andrei [34K]

Answer:

177.1 L

Explanation:

The excersise can be solved, by the Ideal Gases Law.

P . V = n . R . T

In first step we need to determine the moles of gas:

We convert T° from, C° to K → 20°C + 273 = 293K

We convert P from mmHg to atm → 760 mmHg = 1atm

1Dm³ = 1L → 190L

We replace: 190 L . 1 atm = n . 0.082 . 293K

(190L.atm) / 0.082 . 293K = 7.91 moles.

We replace equation at STP conditions (1 atm and 273K)

V = (n . R .T) / P

V = (7.91 mol . 0.082 . 273K) / 1atm = 177.1 L

We can also make a rule of three:

At STP conditions 1 mol of gas occupies 22.4L

Then, 7.91 moles will be contained at (7.91 . 22.4) /1 = 177.1L

3 0
3 years ago
How is the pH of an acidic substance raised?
ch4aika [34]

Explanation:

An acid is a substance that produces excess hydroxonium ions in solution.

An acid based on the pH scale is a substance that has a low pH. Acid lies within a range of 1-7 on the pH scale.

  • A pH of 7 is for neutral compounds like water.
  • A pH greater that 7 is for basic compounds.
  • In order to raise the pH, we are driving at a substance becoming more neutral or basic.

This can be achieved by adding more base to the solution of the substance. When we add more base, hydroxyl ions will neutralize the excess hydroxonium ions and drag the pH towards that of neutrality.

Addition of more base can eventually make the substance basic.

learn more:

Phosphoric acid brainly.com/question/11062486

#learnwithBrainly

4 0
2 years ago
Read 2 more answers
In methane combustion, the following reaction pair is important: At 1500 K, the equilibrium constant Kp has a value of 0.003691
andre [41]

Explanation:

Let us assume that the value of K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{T}}) m^{6}/mol^{2}s

Also at 1500 K, K_{r} = 2.82 \times 10^{5} \times e^({\frac{-9835}{1500}}) m^{6}/mol^{2}s

                     K_{r} = 400.613 m^{6}/mol^{2}s

Relation between K_{p} and K_{c} is as follows.

                  K_{p} = K_{c}RT

Putting the given values into the above formula as follows.

                  K_{p} = K_{c}RT

         0.003691 = K_{c} \times 8.314 \times 1500

                K_{c} = 2.9 \times 10^{-7}

Also,     K_{c} = \frac{K_{f}}{K_{r}}

or,                K_{f} = K_{c} \times K_{r}

                               = 2.9 \times 10^{-7} \times 400.613

                               = 1.1617 \times 10^{-4} m^{6}/mol^{2}s

Thus, we can conclude that the value of K_{f} is 1.1617 \times 10^{-4} m^{6}/mol^{2}s.

6 0
3 years ago
Which of the following examples describes an increase in potential energy? Question 1 options: a basketball falling through a ne
MArishka [77]
Paint being carried up a ladder
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Which of these is indication that a chemical reaction has occurred?
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B.melting of a substance
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