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slavikrds [6]
3 years ago
8

What are the products in this chemical reaction? 2H3PO4+3Ca(OH)2→Ca3(PO4)2+6H2O

Chemistry
2 answers:
Ksju [112]3 years ago
8 0

Answer:

C)  Ca3(PO4)2 and 6H2O

Explanation:

finlep [7]3 years ago
5 0
<h2>Answer:C</h2>

Explanation:

A chemical equation is a equation that describes a corresponding chemical reaction.

A chemical reaction is generally written as

reactants→products

reactants refer to all the reactants involved in the chemical reaction.

Reactants are usually written on the left hand side of the chemical equation.

products refer to all the products formed in the chemical reaction.

products are usually written on the right hand side of the chemical equation.

In the given reaction,Ca_{3}(PO_{4})_{2},H_{2}O are written on the right side of the equation.

So,Ca_{3}(PO_{4})_{2},H_{2}O are the products.

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How long will it take for a 750 mg sample of radium with a half life of 15 days to decay to exactly 68mg?
weqwewe [10]

Answer:

52 da  

Step-by-step explanation:

Whenever a question asks you, "How long to reach a certain concentration?" or something similar, you must use the appropriate integrated rate law expression.

The i<em>ntegrated rate law for a first-order reaction </em>is  

ln([A₀]/[A] ) = kt

Data:

[A]₀ = 750 mg

 [A] =    68 mg

t_ ½ =   15 da

Step 1. Calculate the value of the rate constant.

 t_½ = ln2/k     Multiply each side by k

kt_½ = ln2         Divide each side by t_½

      k = ln2/t_½

         = ln2/15

         = 0.0462 da⁻¹

Step 2. Calculate the time

ln(750/68) = 0.0462t

         ln11.0 = 0.0462t

            2.40 = 0.0462t     Divide each side by 0.0462

                   t = 52 da

8 0
3 years ago
Calculate the equilibrium constant for the decomposition of water 2h2o(l)  2h2(g) + o2(g) at 25°c, given that g°f (h2o(l)) = –
kow [346]

Answer:

2.6 ×10^-42

Explanation:

From

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R= 8.314 Jmol-1K-1

T= 25°C + 273= 298K

-237.2×10^3= 8.314 × 298 × ln K

ln K= -237.2×10^3/2477.572

K = 2.6 ×10^-42

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4 years ago
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4 0
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Artemon [7]

Answer:

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