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slavikrds [6]
3 years ago
8

What are the products in this chemical reaction? 2H3PO4+3Ca(OH)2→Ca3(PO4)2+6H2O

Chemistry
2 answers:
Ksju [112]3 years ago
8 0

Answer:

C)  Ca3(PO4)2 and 6H2O

Explanation:

finlep [7]3 years ago
5 0
<h2>Answer:C</h2>

Explanation:

A chemical equation is a equation that describes a corresponding chemical reaction.

A chemical reaction is generally written as

reactants→products

reactants refer to all the reactants involved in the chemical reaction.

Reactants are usually written on the left hand side of the chemical equation.

products refer to all the products formed in the chemical reaction.

products are usually written on the right hand side of the chemical equation.

In the given reaction,Ca_{3}(PO_{4})_{2},H_{2}O are written on the right side of the equation.

So,Ca_{3}(PO_{4})_{2},H_{2}O are the products.

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What is meant by the term activation energy?
Zinaida [17]
The least amount of energy required to activate atoms or molecules to a state in which they can undergo a chemical reaction.
5 0
3 years ago
What is oxidized and what is reduced <br> C2H4 + 2O2 → 2CO + 2H2O<br> C2H4 + 3O2 → 2CO2 + 2H2O
Anika [276]

C2H4 is oxidized and O2 is reduced in both reactions.

<h3>What is oxidation/reduction?</h3>

Oxidation is defined in several ways. Some of the definitions are:

  1. The addition of oxygen or removal of hydrogen
  2. Increase in the oxidation number of atoms
  3. Addition of electronegative or the removal of electropositive elements

Reduction, on the other hand, is defined as:

  1. Removal of oxygen or addition of hydrogen
  2. Decrease in the oxidation number of atoms
  3. Addition of electropositive elements or the removal of electronegative elements.

In the two reactions, oxygen is being added to C2H4. Thus, C2H4 is being oxidized.

The oxidizing agent is O2. In oxidation reactions, the oxidizing agents usually get reduced. Thus, O2 is reduced in both reactions.

More on oxidation and reduction can be found here: brainly.com/question/3867774

#SPJ1

7 0
1 year ago
Consider the following reaction where K. = 9.52 10 2 at 350 K.
Harman [31]

Answer:

The correct answer is A :))

3 0
2 years ago
In IR spectroscopy, we normally talk about "frequencies" when in reality we are referring to wavenumbers. What is the mathematic
Svetach [21]

Answer:

Here's what I get.

Explanation:

(b) Wavenumber and wavelength

The wavenumber is the distance over which a cycle repeats, that is, it is the number of waves in a unit distance.

\bar \nu = \dfrac{1}{\lambda}

Thus, if λ = 3 µm,

\bar \nu = \dfrac{1}{3 \times 10^{-6} \text{ m}}= 3.3 \times 10^{5}\text{ m}^{-1} = \textbf{3300 cm}^{-1}

(a) Wavenumber and frequency

Since

λ = c/f and 1/λ = f/c

the relation between wavenumber and frequency is

\bar \nu = \mathbf{\dfrac{f}{c}}

Thus, if f = 90 THz

\bar \nu = \dfrac{90 \times 10^{12} \text{ s}^{-1}}{3 \times 10^{8} \text{ m$\cdot$ s}^{-1}}= 3 \times 10^{5} \text{ m}^{-1} = \textbf{3000 cm}^{-1}

(c) Units

(i) Frequency

The units are s⁻¹ or Hz.

(ii) Wavelength

The SI base unit is metres, but infrared wavelengths are usually measured in micrometres (roughly 2.5 µm to 20 µm).

(iii) Wavenumber

The SI base unit is m⁻¹, but infrared wavenumbers are usually measured in cm⁻¹ (roughly 4000 cm⁻¹ to 500 cm⁻¹).

8 0
3 years ago
The addition of phosphate to a chemical compound is called A. glycolysis. B. oxidation. C. reduction. D. phosphorylation.
stich3 [128]

Answer:

Option (D)

Explanation:

Phosphorylation can be simply defined as the addition of a phosphate group to an organic and inorganic molecule. This process helps in regulating the processes that occur in the cells. It leads to the growth and development of cells and this process is efficiently carried out with the help of enzymes like kinase. It also plays an important role in transferring the signals within the cells, synthesis, and functioning of proteins within the cells, and storing as well as releasing of energy.

Thus, the correct answer is option (D).

5 0
3 years ago
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