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1 year ago

Which of the following rules is applicable for balancing a chemical equation?

Chemistry

1 answer:

Ber [7]1 year ago

7 0

Answer:

A.) Change only the coefficients

Explanation:

An equation is balanced when there is an equal quantity of each type of element on both sides of a reaction. When balancing an equation, the only way to manipulate the amounts of each element is by changing the coefficient values. The coefficients alter the amount of each molecule in the reaction.

The subscripts cannot be altered. If you were to change the subscripts, you would be altering the amount of atoms in a particular molecule.

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7nadin3 [17]

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Explanation:

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2 years ago

Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain

RoseWind [281]

Answer:

$M_{per}= 52.86$

$W_{per}=47.14$

Explanation:

<u>First mixture</u>:

40 wt% methanol - 60 wt% water 200 kg

$m_{met1}=200 kg * 0.4= 80 kg$

$m_{wat1}=200 kg * 0.6= 120 kg$

<u>Second mixture</u>:

70 wt% methanol - 30 wt% water 150 kg

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$m_{wat2}=150 kg * 0.3= 45 kg$

Final mixture:

$m_{metF=80 kg + 105 kg= 185 kg$

$m_{watF}=120 kg + 45 = 165 kg$

$M_{per}=\frac{185 kg}{185 kg + 165 kg}*100= 52.86$

$W_{per}=\frac{165 kg}{185 kg + 165 kg}*100=47.14$

If, the compositions are constant, the only variables are the mass of each mixture used in the final one, so there can be only one independent balance.

8 0

3 years ago

What is the volume of 2.10 moles of chlorine gas (Cl2) at 273 K and 1.00 atm?

Rasek [7]

Ideal gas law:
PV=nRT ⇒ V=nRT / P
P=pressure=1 atm
V=volume
n=number moles=2.10 moles
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T=temperature=273 K

V=(2.10 moles*0.082 (atm l)/º(K mol)*237ºK) / 1 atm=47.01 litres

47.1 L

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3 years ago

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wolverine [178]

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