Answer: Option 1 is the answer
Answer:
The provided equation is an identity.
Step-by-step explanation:
Answer: 30g
Step-by-step explanation:
In this question (t½) of isotope is 40 days, which means that after 40 days half of the sample would have decayed and half would be left as it is.
After 40 days ( first half life) 240 /2 = 120 g decays and 120 g remains left.
After another 40 days ( two half lives or 80 days) 120 /2 = 60 g decays and 60 g remains left .
after three half lives or 120 days, 60/2 = 30g decay and 30 g of the isotope will be left.
Answer:
Answer will be 28
Step-by-step explanation:
We have to find the GCF( LCM(8,14) , LCM (7,12) )
Here GCF is stands for greatest common factor and LCM is stands for lowest common factor
Let first find LCM of (8,14)
8 = 2×2×2
14 = 2×7
So LCM will be 2×2×2××7 = 56
Now LCM of (7,12)
7 = 7×1
12 = 2×2×3
So LCM will be 2×2×3×7 = 84
Now GCF of (56,84)
56 = 2×2×2×7
84=2×2×3×7
So GCF will be 2×2×7 = 28