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Vera_Pavlovna [14]
2 years ago
15

One mole of which substance contains a total of 6.02 x 1023 atoms? (I need help please.)

Chemistry
1 answer:
Korolek [52]2 years ago
8 0

Answer:

Oxygen

Explanation:

One mole of atoms of oxygen has a mass of 16 g, as 16 is the atomic weight of oxygen, and contains 6.02 X 1023 atoms of oxygen.

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Calculate the volume of a gas at a pressure of 150 kpa if its volume at 180 kpa is 1500 L
Anastaziya [24]

Answer: 1800 L

Explanation:

Given that,

Original pressure of gas (P1) = 180 kPa

Original volume of gas (V1) = 1500 L

New pressure of gas (P2) = 150 kPa

New volume of gas (V2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P1V2

180 kPa x 1500 L = 150 kPa x V2

270000 kPa•L = 150 kPa•V2

Divide both sides by 150 kPa

270000 kPa•L/150 kPa = 150 kPa•V2/150 kPa

1800L = V2

Thus, the new volume of the gas is 1800 liters.

8 0
3 years ago
The global movement of air occurs in convection cells. In general,how does air move
borishaifa [10]
Air moves when the molecules are free meaning they aren't close up to each other or trying to fill up space, they are moving freely. 
6 0
3 years ago
At STP, solid carbon can exist as graphite or as diamond. These two forms of carbon have(1) the same properties and the same cry
Umnica [9.8K]
Answer=4

Diamonds and graphite have different properties and different crystal structures.

In diamonds, the carbon atoms are arranged tetrahedrally, whereas carbon atoms are arranged in an infinite array in graphite. Graphite has a lower density than diamonds... Diamonds are the best conductor of heat that we know of... the properties differ greatly 
3 0
3 years ago
Melting gold with other metals makes 10-karat gold. Which term best describes 10-karat gold?(1 point)
Arte-miy333 [17]
2heterroge is the answer
4 0
2 years ago
Determine the theoretical yield and the percent yield if 21.8 g of K2CO3 is produced from reacting 27.9 g KO2 with 57.0 g CO2. T
Alex_Xolod [135]

Answer:

26.9 g

81%

Explanation:

The equation of the reaction is;

4 KO2(s) + 2 CO2(g) → 3 O2(g) + 2 K2CO3(s)

Number of moles of KO2= 27.9g/71.1 g/mol = 0.39 moles

4 moles of KO2 yields 2 moles of K2CO3

0.39 moles of KO2 yields 0.39 × 2/4 = 0.195 moles of K2CO3

Number of moles of CO2 = 57g/ 44.01 g/mol = 1.295 moles

2 moles of CO2 yields 2 moles of K2CO3

1.295 moles of CO2 yields 1.295 × 2/2 = 1.295 moles of K2CO3

Hence the limiting reactant is KO2

Theoretical yield = 0.195 moles of K2CO3 × 138.205 g/mol = 26.9 g

Percent yield = actual yield/theoretical yield × 100

Percent yield = 21.8/26.9 × 100

Percent yield = 81%

5 0
3 years ago
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