1: the symbol of the metal should be written first.
2: the valency of the elements or radicals should be interchanged.
Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
The 2-bromo-1-chloro-2-methylpropane molecule contains a total of 14 atom(s). There are 4 Carbon atom(s), 8 Hydrogen atom(s), 1 Chlorine atom(s) and 1 Bromine atom(s). A chemical formula of 2-bromo-1-chloro-2-methylpropane can therefore be written as C4H8BrCl. Is it also commonly called as Propane.
According to Boyle's law, if the temperature were tripled as the number of moles and the volume were held constant, the pressure would triple (option C).
<h3>What is Boyle's law?</h3>
Boyle's law is the observation that the pressure of an ideal gas is inversely proportional to its volume at constant temperature.
However, when the temperature of a gas is increased, the pressure of the gas also increases provided the volume is constant.
According to this question, the temperature of a gas tripled as the number of moles and the volume were held constant.
Therefore, according to Boyle's law, if the temperature were tripled as the number of moles and the volume were held constant, the pressure would triple.
Learn more about Boyle's law at: brainly.com/question/1437490
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Answer:
2.11 * 10^3 molecules of phosphoric acid
Explanation:
