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Crank
3 years ago
12

How does respiration differ from cellular respiration?

Chemistry
1 answer:
ipn [44]3 years ago
6 0
Breathing involves inhale of oxygen from the atmosphere into the lungs and exhale of carbon dioxide from the lungs into the atmosphere ; whereas cellular respiration involves breakdown of glucose into carbon dioxide and water in living cells, releasing energy.
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Compound 1 has a composition of 46.7 mass % of element A and 53.3 mass % of element B. A and B also form a second binary compoun
Leviafan [203]

A summary of the Law of multiple proportions is that if A and B form more than one compound, and B1 is the amount of element B which reacts with a fixed mass of A in compound 1, and B2 is the amount of B which reacts with the same fixed mass of B to form compound 2, then the ratio B1:B2 will be small whole numbers.

This law is rather simplistic, and given the range of compounds known today the definition of 'small' is now rather large... but, to answer the question:

in compound one 1.14133g of B reacts with 1g of A. (1.14133=53.3/46.7)  

5 0
3 years ago
Which of these substances are molecules?
Tamiku [17]

Answer:

c) none of them

Explanation:

because H20, N2 , O2 are all molecules except NaCl so there is no answers like ( 1, 3, and4 ) so we choose none of them.

6 0
3 years ago
Which of the following statements correctly describes boyle's law
abruzzese [7]

<span>In the said law, the volume of a gas varies inversely with pressure. Boyle's law is one of the gas laws we have. According to this law, at a fixed amount of an ideal gas which is at constant temperature, the pressure and volume are inversely proportional with each other. <span>The variables are volume and pressure.</span></span>

3 0
3 years ago
In order to determine if 2 atoms are cooper what must be the same for each
galina1969 [7]
-number of electrons
-atom size
-charge of the atom
-number of protons
4 0
3 years ago
I need you to solve for me plzzzzzz
Sergeu [11.5K]

Answer:

.0556 L

Explanation:

First, convert the 1.35 M to 1.35 mol/L in order for the units to correctly cancel out.

Then, multiply (0.0725 moles Na2CO3/1) times (L/ 1.35 mol).

Finally, the answer will be .0556 L.

<h3 />
3 0
2 years ago
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