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3 years ago

A mole of hydrogen atoms has 6.02 x 10^23 atoms. It occupies 22.414 L. How many hydrogen atoms are in 50.00 mL?

Chemistry

1 answer:

Greeley [361]3 years ago

3 0

Answer:

This is a simple case of ratios. (1 mol)/(22.4 L)=(n mol)/(.025 L) Then we cross multiply and we get 22.4n=.025 We divide each side by 22.4 to find n=.001116 mol Then to convert the moles to atoms we multiply, and cross-cancel the units (.001116 mol)/1 xx (6.02 xx 10^23 atms)/(1 mol) and we have 6.72 xx 10^20 atoms. I've found the trick of cross-cancelling units to be a very effective mnemonic, it always makes sure you carry out the correct calculation to find the desired units.

Explanation:

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Answer:

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Explanation:

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Heat that flows by conduction is the transfer of thermal energy between substances in contact. What must occur forth

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One system must have higher kinetic energy than the other system

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3 years ago

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Fill in the blanks with appropriate options given in below:

jarptica [38.1K]

Answer:

1) -COOH

2) -NH2

3) hydrogen bonds

4) dispersion forces

5) -CH3

6) hydrogen bonds

7) negative

8) negative

9) positive

Explanation:

Alanine has a -COOH and a -NH2 group available to form hydrogen bonds with water molecules.

Although there are some potential dispersion forces between the terminal -CH3 group of alanine and hexane molecules, we expect the hydrogen bonds between alanine and water to be stronger.

Stronger intermolecular attractive forces between alanine and water lead to a more negative ΔHmix and more negative (smaller positive) ΔHsoln for water than for hexane.

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The density of an unknown gas is 4. 20 grams per liter at 3. 00 atmospheres pressure and 127 °c. what is the molecular weight of

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The molecular weight of this gas will be 45 g/mol .

The state equilibrium equation for a fictitious perfect gas is known as the ideal gas law, sometimes known as the generic gas equation. Although it has significant drawbacks, it represents a decent approximation of the activity of many gases under various conditions.

Ideal gas law can be expressed as:

PV =nRT

Calculation of molecular weight by using ideal as law.

Given data:

P = 3 atm

T = 127 °c

Density = 4. 20 grams per liter

PV =nRT

where p is pressure , T is temperature and R is gas constant.

PV = gram / molecular weight RT

Molecular weight = (g/v)( 1/P) RT

Putting the given data in above equation.

Molecular weight =4.20 × 1/ 3× 400 × 0.0831

Molecular weight = 45 g/mol.

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Answer:

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Explanation:

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