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Bas_tet [7]
2 years ago
11

Identify the correct type of heat transfer for A, B, and C in the picture. Using the picture, cite evidence for your choices.

Chemistry
1 answer:
tatiyna2 years ago
6 0

The correct type of heat transfer for A, B, and C are conduction, convection and radiation respectively.

<h3>What is heat transfer?</h3>

Heat transfer is a process in which amount of heat will be transferred from one object to any other object by various means.

  • In type A, heat is transferred through conduction process as in this transfer takes place due to direct contact of particles.
  • In type B, heat is transferred through the convection process as in that process transfer of heat takes place through the medium.
  • In type C, heat transfer done by the radiation as in that transfer through empty space.

Hence at A, B and C heat transfer done through conduction, convection and radiation respectively.

To know more about heat transfer, visit the below link:

brainly.com/question/2341645

#SPJ1

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The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
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<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

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<h3><u><em>Option D: Evapotranspiration  </em></u></h3>

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