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Ira Lisetskai [31]
3 years ago
9

Is cutting grass of physical change or chemical change

Chemistry
2 answers:
leva [86]3 years ago
6 0
Cutting the grass would be other irreversible physical changes.
storchak [24]3 years ago
4 0

Answer:

physical

Explanation:

you have to do it ur self

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What is kinetic energy? *
finlep [7]

Answer:

energy which a body possesses by virtue of being in motion

Explanation:

the work needed ro accelerate a body of given mass

4 0
2 years ago
What is the formula for nitrogen monoxide?
WINSTONCH [101]
The answer is NO.

Mono- means 1, so monoxide would indicate that there is 1 oxygen.

The N is double bonded to the O:

N=O

And has an unpaired set of electrons
4 0
3 years ago
Decreasing the temperature of the reaction 3H2 + N2 2NH3. In this reaction, the product absorbs heat. WHICH WAY WILL THE REACTIO
Alex

Answer:

the reaction will shift towards the “heat”—shifts to the left

Explanation:

To summarize:

o If temperature increases (adding heat), the reaction will shift away from the “heat” term and go in the

endothermic direction.

o If temperature decreases (removing heat), the reaction will shift towards the “heat” term and go in the

exothermic direction.

o NOTE: The endothermic direction is always away from the “heat” term and the exothermic direction is

towards the “heat” term.

Therefore the reaction will shift towards the “heat”—shifts to the left

3 0
3 years ago
Quien inventó la electricidad
makvit [3.9K]
Can you put this in english

6 0
3 years ago
Occupational Safety and Health Administration has set the limit on the maximum percentage of carbon dioxide (CO2) in air a worke
Lyrx [107]

Answer:

The minimum rate of fresh air in the room is 176 moles/min

Explanation:

High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.

0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air

As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:

\frac{0,500 moles CO_{2}}{100 moles Air} = \frac{0,880 moles CO_{2}/min}{X}

X = <em>176 moles of Air/min</em>

<em></em>

I hope it helps!

4 0
3 years ago
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