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zvonat [6]
1 year ago
13

What are 5 examples of monosaccharides? What is also known as monosaccharide?​

Chemistry
1 answer:
kondaur [170]1 year ago
6 0
1. Fructose
2. Proteins
3. Glucose
4. Ribose
5. Galactose.
This is also called sugar, or carbohydrates.
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Determine the formula weight of caffeine, C₈H₁₀N₄O₂. Provide an answer to two decimal places.
arlik [135]

Let's find

\\ \tt\hookrightarrow C_8H_10N_4O_2

  • We need accurate mass

\\ \tt\hookrightarrow 8(12.011)+10(1.007)+4(14.006)+2(16.0)

\\ \tt\hookrightarrow 96.088+10.07+56.024+32.0

\\ \tt\hookrightarrow 196.182g/mol

\\ \tt\hookrightarrow 196.18g/mol\:or 196.18u

5 0
2 years ago
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HELPPPP PLEASEE!!!!!!!
OlgaM077 [116]

I think the answer is yes

3 0
2 years ago
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Which of the following conditions creates the largest waves?
SashulF [63]

Answer:

strong winds that blow in short spurts over a small distance

Explanation:

Generally, the most common factor that causes the largest waves in the ocean is winds. this is also called wind-driven waves of the ocean when the surface wind flows on the surface of the ocean, this disturbance creates the friction between surface wind and surface of the ocean which creates waves in the ocean

6 0
3 years ago
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Given that kb for c6h5nh2 is 1.7 × 10-9 at 25 °c, what is the value of ka for c6h5nh3 at 25 °c?
lina2011 [118]

Answer: k_a for C_6H_5NH_3^+ at 25°C is 0.588\times 10^{-4}

Explanation: We are given k_b of C_6H_5NH_2 at 25°C which is 1.7\times 10^{-9}

To calculate the k_a of C_6H_5NH_3^+, we use the formula:

k_w=k_a\times k_b

k_w\text{ at }25^o=1\times 10^{-14}

Putting values in above equation, we get:

1\times 10^{-14}=k_a\times (1.7\times 10^{-9})\\k_a=0.588\times 10^{-5}

7 0
3 years ago
Determine the concentrations of mgcl2, mg2 , and cl– in a solution prepared by dissolving 2.75 × 10–4 g mgcl2 in 1.75 l of water
inysia [295]

Answer:


M of MgCl₂ = 1.65 × 10⁻⁶ M


M of Mg²⁺ = 1.65 × 10⁻⁶ M


M of Cl⁻ = 3.30 × 10⁻⁶ M



Explanation:



1) MgCl₂


Molarity = number of moles of solute / volume of solution in liters, M = n / V


n = mass in grams / molar mass


molar mass of MgCl₂ = 24.305 g/mol + 2(35.543 g/mol) = 95.211 g/mol


n = 2.75 × 10⁻⁴ g / 95.211 g/mol = 2.89×10⁻³ moles


⇒ M = n / V = 2.89×10⁻³ moles / 1.75 l = 1.65 × 10⁻⁶ M



2) Mg²⁺ and Cl⁻


Those are the ions in solution.


You assume 100% dissociation of the ionic compound (strong electrolyte).


Then the equation is: MgCl₂ → Mg²⁺ + 2Cl⁻


That means that 1 mol of MgCl₂ produces 1 mol of Mg²⁺ and 2 moles of Cl⁻.


That yields the same molarity concentration of Mg²⁺ , while the molarity concentration of Cl⁻ is the double.



So, the results are:


M of MgCl₂ = 1.65 × 10⁻⁶ M


M of Mg²⁺ = 1.65 × 10⁻⁶ M


M of Cl⁻ = 3.30 × 10⁻⁶ M

8 0
2 years ago
Read 2 more answers
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