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Tresset [83]
3 years ago
11

Can someone help me w 20 ASAP!!

Chemistry
1 answer:
poizon [28]3 years ago
3 0

Answer: TOOOOOOOOOOOOOOOOOOOO

Explanation:

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Nitrogen family - 5 valence electrons
Anna11 [10]

Answer:

  • <u>The elements that belong to the nitrogen family are nitrogen, phosphorus, arsenic, antimonium, bismuth, and moscovium.</u>

Explanation:

<em>Families</em> are group of elements that belong to the same column in the periodic table.

Some families have a well known name. For instance, alkali metals is the family of the elements that belong to the first column: Li, Na, K, Rb, Cs, and Fr (H is an exception, in spite it is in the first column it does not belong to the alkali metals family because it is a nonmetal). Other well known families are alkaline earth metals (column 2), halogens (column 3), and noble gases (column 18).

All the members of a family have the same number of valence electrons, i.e. electrons in the outermost shell.

  • <u>Nitrogen</u>, N, is in the column 15; it has 5 valence electrons, because its outer most shell has configurarion ns²np³ (n is 2 because nitrogen is in the second period).

The other members fo this family with the electron configuration of the outermost shell are:

  • <u>Phosphorus</u>, P, 3s² 3p³ (third period)

  • <u>Arsenic,</u> As, 4s² 4p³ (fourth period)

  • <u>Antimonium</u>, Sb, 5s² 5p³ (fith period)

  • <u>Bismuth</u>, Bi, 6s² 6p³ (sixth period)

  • <u>Moscovium</u>, Mc, 7s² 7p³ (seventh period)

6 0
3 years ago
Taylor, a MIC 206 student needs to determine the OCD of a sample of Escherichia coli. She performed dilutions using four 9 ml di
Troyanec [42]

Answer:

1.37 x 10^6 CFU/mL

Explanation:

First, the dilution factor needs to be calculated.

Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of 10^{-4}.

Next is to divide the colony forming unit from the dilution by the dilution factor:

   137/10^{-4} = 137 x 10^4

In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.

   137 x 10^4/1 = 1.37 x 10^6

Hence, the CFU/ml present in the original <em>E. coli </em> sample is 1.37 x 10^6.

cfu/ml = (no. of colonies x dilution factor) / volume of culture plate

7 0
4 years ago
The compound consists of 40% carbon and 6.71% hydrogen. Its mass of 1 liter of steam is 2.4 g. What is the formula of the compou
AveGali [126]

I think it is CH2O.

If i'm wrong srry

7 0
3 years ago
What is the volume of 1 lb of mercury. the density of mercury is 13.546g/ml?
joja [24]
<span>Take the inversion of density: 1mL/13.6 g and multiply it by the conversion factor 453.6 g/ 1 lb and the given 5.00 lb. Units for mass (grams) and units for weight (lbs) cancel leaving only units of volume. I believe it should be 167 mL or 0.167 L</span>
7 0
3 years ago
Help me out please due tomorrow
skelet666 [1.2K]
I'm pretty sure number 48 is C. Hope this helped :)
6 0
3 years ago
Read 2 more answers
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