Answer:
(NH₄)₂CO₃ (aq) + MgSO₄(aq) → (NH₄)₂SO₄(aq) + MgCO₃ (s) ↓
Explanation:
We determine the reactants:
(NH₄)₂CO₃ → Ammonium carbonate
MgSO₄ → Magnesium sulfate
We determine the products:
(NH₄)₂SO₄ ; MgCO₃
All the salts from carbonates are precipitates:
(NH₄)₂CO₃ (aq) + MgSO₄(aq) → (NH₄)₂SO₄(aq) + MgCO₃ (s) ↓
Ratio is all 1:1. 1 mol of ammonium carbonate reacts to 1 mol of magnessium sulfate in order to produce 1 mol of ammonium sulfate and 1 mol of magnessium carbonate.
Answer:
There is 17.1 kJ energy required
Explanation:
Step 1: Data given
Mass of ethanol = 322.0 grams
Initial temperature = -2.2 °C = 273.15 -2.2 = 270.95K
Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K
Specific heat capacity = 2.44 J/g*K
Step 2: Calculate energy
Q = m*c*ΔT
⇒ m = the mass of ethanol= 322 grams
⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K
⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K
Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ
There is 17.1 kJ energy required
