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Tresset [83]
3 years ago
11

Can someone help me w 20 ASAP!!

Chemistry
1 answer:
poizon [28]3 years ago
3 0

Answer: TOOOOOOOOOOOOOOOOOOOO

Explanation:

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Would you expect the wavelength of maximum absorbance for [Cu(NH3)4]2+ to be greater than or less than the wavelength of maximum
DENIUS [597]

Answer:

Less

Explanation:

Since [Cu(NH3)4]2+ and [Cu(H2O)6]2+ are Octahedral Complexes the transitions between d-levels explain the majority of the absorbances seen in those chemical compounds. The difference in energy between d-levels is known as ΔOh (ligand-field splitting parameter) and it depends on several factors:

  • The nature of the ligand: A spectrochemical series is a list of ligands ordered on ligand strength. With a higher strength the ΔOh will be higher and thus it requires a higher energy light to make the transition.
  • The oxidation state of the metal: Higher oxidation states will strength the ΔOh because of the higher electrostatic attraction between the metal and the ligand

A partial spectrochemical series listing of ligands from small Δ to large Δ:

I− < Br− < S2− < Cl− < N3− < F−< NCO− < OH− < C2O42− < H2O < CH3CN < NH3 < NO2− < PPh3 < CN− < CO

Then NH3 makes the ΔOh higher and it requires a higher energy light to make the transition, which means a shorter wavelength.

7 0
4 years ago
How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas?
Vladimir [108]
Note that it says oxygen "gas"
So you need the atomic mass of oxygen gas

Look at your periodic table, you'll see 15.9994 under oxygen
Oxygen gas has a formula of O2 therefore,
(15.9994) times 2= Oxygen gas atomic mass=31.9988

Mol= Mass/Atomic Mass
=62.3 g/ 31.9988 g/mol = 1.95 mol

now look at the ratio of C2H6 and O2, notice there is an invisible number beside each of them, at that "invisible number" is =1

1 C2H6 + 1 O2 -> products

this means that for 1 mol of C2H6, 1 mol of O2 has to react with it

Thus as we have 1.95 moles of O2, we need 1.95 moles of C2H6
5 0
3 years ago
Be sure to answer all parts.The equilibrium constant, Kc, for the formation of nitrosyl chloride from nitric oxide and chlorine,
djverab [1.8K]

<u>Answer:</u> The reaction proceeds in the forward direction

<u>Explanation:</u>

For the given chemical equation:

2NO(g)+Cl_2(g)\rightleftharpoons 2NOCl(g)

Relation of K_p\text{ with }K_c is given by the formula:

K_p=K_c(RT)^{\Delta n_g}

where,

K_p = equilibrium constant in terms of partial pressure = ?

K_c = equilibrium constant in terms of concentration = 6.5\times 10^4

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 35^oC=[35+273]K=308K

\Delta n_g = change in number of moles of gas particles = n_{products}-n_{reactants}=2-3=-1

Putting values in above equation, we get:

K_p=6.5\times 10^4\times (0.0821\times 500)^{-1}\\\\K_p=1583.43

K_p is the constant of a certain reaction at equilibrium while Q_p is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

The expression of Q_p for above equation follows:

Q_p=\frac{(p_{NOCl})^2}{p_{Cl_2}\times (p_{NO})^2}

We are given:

p_{NOCl}=1.76atm

p_{NO}=1.01atm

p_{Cl_2}=0.42atm

Putting values in above equation, we get:

Q_p=\frac{(1.76)^2}{0.42\times (1.01)^2}=7.23

We are given:

K_p=1583.43

There are 3 conditions:

  • When K_{p}>Q_p; the reaction is product favored.
  • When K_{p}; the reaction is reactant favored.
  • When K_{p}=Q_p; the reaction is in equilibrium

As, K_p>Q_p, the reaction will be favoring product side.

Hence, the reaction proceeds in the forward direction

4 0
3 years ago
Select the answer that CANNOT be used to fill in the blank in the following sentence:
Mashcka [7]

Answer:

3. move more quickly

Explanation:

...................

6 0
4 years ago
Calculate the volume of hydrogen if you have 12.1 moles of Hydrogen.
vodomira [7]

To Find :

The volume of 12.1 moles hydrogen at STP.

Solution :

We know at STP, 1 mole of gas any gas occupy a volume of 22.4 L.

Let, volume of 12.1 moles of hydrogen is x.

So, x = 22.4 × 12.1 L

x = 271.04 L

Therefore, the volume of hydrogen gas at STP is 271.04 L.

8 0
3 years ago
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