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3 years ago

What order do they go in plz someone help

Chemistry

2 answers:

beks73 [17]3 years ago

5 0

Oceanic crust, continental crust, mantle, the inner and outer core. Hope this helped and I hope it’s right!

kotegsom [21]3 years ago

4 0

Continental crust, oceanic crust, mantle , outer core , and inner core.

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What is the symbol of the element that has the electron configuration 1s22s22p63s23p64s23d5?

ira [324]

Just add up all the "exponents" and you'll get 25 which is Manganese or Mn on the periodic table!

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3 years ago

The dimensions of a cupboard are 1.31 m wide

Mnenie [13.5K]

Answer:

The volume of cupboard is 2.0043 m³.

Explanation:

Given data:

width of cupboard = 1.31 m

length of cupboard = 0.9 m

height of cupboard = 1.70 m

Volume = ?

Solution:

Volume = length × width × height

Volume = 0.9 m × 1.31 m × 1.70 m

Volume = 2.0043 m³

The volume of cupboard is 2.0043 m³.

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3 years ago

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When calcium carbonate reacts with hydrogen chloride, if the reaction occurs with 78.5% yield, what mass of carbon dioxide will

Vilka [71]

97.95 is the answer to the question

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4 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

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Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL from C12H22O11

fgiga [73]

Answer:

34.23 g.

Explanation:

Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of C₁₂H₂₂O₁₁/(V of the solution (L)).

∴ mass of C₁₂H₂₂O₁₁ = (M)(molar mass)(V of the solution (L) = (1.0 M)((342.3 g/mol)/(0.10 L) = 34.23 g.

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4 years ago