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3 years ago

Plz answer will give BRAINLIEST! Promise! Question is in picture! Due in 5 minutes!!

Chemistry

1 answer:

zvonat [6]3 years ago

4 0

Answer:

try A

Explanation:

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During a phase change, the temperature remains ________. After the change of state occurs, the temperature ________.

lozanna [386]

Answer:

The temperature remains constant. after the change occurs and temp remains the same

Explanation:

Remains constant because the phase change is absorbing the energy, after the phase change occurs it is then increasing in temperature again.

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3 years ago

Which statement correctly describes a difference between aesexual and sexual reproduction?

mote1985 [20]

Answer:

(3rd option) Asexually reproduced offsprings have the same amount of genetic information as the parent, while sexually reproduced offsprings have half as much genetic information.

Explanation:

This is variation is caused as a result of both gamete production and fertilisation.

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3 years ago

What are even covalent chlorides? Question D

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The chlorine atom (or atoms) is covalently bonded by a shared pair of electrons to the other element.

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3 years ago

An engineer that desings buildings is a(n)_____.

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An engineer that designs buildings is a structural engineer.

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2 years ago

Calculate the pH for the following weak acid. A solution of HCOOH has 0.12M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4.

Shtirlitz [24]

Answer:

the pH of HCOOH solution is 2.33

Explanation:

The ionization equation for the given acid is written as:

$HCOOH\leftrightarrow H^++HCOO^-$

Let's say the initial concentration of the acid is c and the change in concentration x.

Then, equilibrium concentration of acid = (c-x)

and the equilibrium concentration for each of the product would be x

Equilibrium expression for the above equation would be:

$\Ka= \frac{[H^+][HCOO^-]}{[HCOOH]}$

$1.8*10^-^4=\frac{x^2}{c-x}$

From given info, equilibrium concentration of the acid is 0.12

So, (c-x) = 0.12

hence,

$1.8*10^-^4=\frac{x^2}{0.12}$

Let's solve this for x. Multiply both sides by 0.12

$2.16*10^-^5=x^2$

taking square root to both sides:

$x=0.00465$

Now, we have got the concentration of $[H^+] .$

$[H^+] = 0.00465 M$

We know that, $pH=-log[H^+]$

pH = -log(0.00465)

pH = 2.33

Hence, the pH of HCOOH solution is 2.33.

7 0

3 years ago

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