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Luden [163]
3 years ago
6

Help!!

Physics
1 answer:
Roman55 [17]3 years ago
5 0
D. Circulatory
The digestive system works very closely with the circulatory system to get the absorbed nutrients distributed through your body. The circulatory system also carries chemical signals from your endocrine system that control the speed of digestion.
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Can anybody answer this its a science question NO LINKS !!!!
Zigmanuir [339]

Answer:

1) Potential energy (gravitation)

2)Potential energy

3)Kinetic energy

4) Kinetic energy

5)Potential energy

6)Kinectic energy

7)Potential energy (elastic)

Hope it helps

8 0
3 years ago
When compared to other types of waves, electromagnetic waves differ because they are
alina1380 [7]
They differ because they are transverse wave. That is their direction of travel is perpendicular to its vibrations. I'm not that sure though. Hope you get it right :).....
5 0
3 years ago
Se lanza desde el suelo verticalmente hacia arriba un objeto con una velocidad inicial de 20 m/s. Calcula: a)Posición y velocida
djverab [1.8K]

Answer:

Ver las respuestas a continuacion.

Explanation:

Para solucionar este tipo de problemas debemos de utilizar la siguiente ecuacion de la cinematica.

a)

v_{f}=v_{o}-g*t

Donde:

Vf = velocidad final [m/s]

Vo = velocidad inicial = 20 [m/s]

g = aceleración gravitacional = 9.81 [m/s²]

t = tiempo = 1 [s]

El signo negativo de la aceleración gravitacional significa que el objeto se mueve en dirección contraria a la aceleración gravitacional.

v_{f}=20-9.81*(1)\\v_{f}=10.19[m/s]

b)

La altura máxima se logra cuando la velocidad final es cero, es decir no existe movimiento alguno para que siga subiendo el objeto. Debemos utilizar la siguiente ecuación de la cinemática.

v_{f}^{2} =v_{o}^{2}-2*g*y

Donde:

y = elevación [m]

0 = 20^{2} -2*9.81*y\\19.62*y=400\\y=20.38 [m]

c)

Podemos calcular el tiempo máximo que toma el objeto en subir.

v_{f}=v_{o}-g*t

0 = 20 -9.81*t\\9.81*t=20\\t=2.04[s]

Ahora del numeral b) sabemos la distancia maxima, de esta manera y utilizando la siguiente ecuacion podemos calcular el tiempo de caida, Debemos tener en cuenta que ahora la velocidad final es igual a la velocidad inicial = 0.

y=y_{o}+v_{o}*t+\frac{1}{2}*g*t^{2}

20.38 = 0*t + 0.5*9.81*t^{2} \\20.38 = 4.905*t^{2}\\t=\sqrt{\frac{20.38}{4.905} } \\t=2.04[s]

Entonces el tiempo total es igual a:

t = 2.04 + 2.04

t = 4.076 [s]

4 0
3 years ago
a net force of 749 newton causes an object to accelerate at 10.6m/s/s. determine the mass of the object in kg
8090 [49]
We know, F = m*a
749 = m * 10.6
m = 749 / 10.6
m = 70.66 Kg

In short, Your Answer would be 70.66 Kg

Hope this helps!
7 0
3 years ago
A closed pipe and an open pipe have their first overtones identical in frequency. their lengths are in the ratio?
yuradex [85]
You should mention that sound waves are generated in identical conditions i.e the speed of sound is same in the two experiments. 
In that case the ratio is
2v/2L1 :  3v/4L2 = 4L2 : 3L1 .
5 0
3 years ago
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