Pls help

This table lists the densities of four different substances.

cestrela7 [59]

Answer:

GREATER than 1 g/cm. 3, it will SINK in water. LESS than 1 g/cm3, it will FLOAT in water. If an object's density is: Density of Object > Density of Liquid.

Explanation:

3 0

3 years ago

What is one advantage of using a computer over a graphing calculator?

Dahasolnce [82]

A computer can show you how it is done and how they got to that solution while a graphing calculator can only show you the solution.

4 0

3 years ago

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Two wheels with fixed hubs, each having a mass of 1kg , start from rest, and forces are applied: F1= 1 N to the first wheel and

irina [24]

Answer:

2N

Explanation:

$m = m_1 = m_2 = 1 kg$

The torques generated by tangential forces on the 2 wheels are

$T_1 = F_1R_1 = 1*0.5 = 0.5 Nm$

$T_2 = F_2R_2 = F_2*1 = F_2 Nm$

According to Newton's 2nd law, the angular accelerations generated by these torque would be

$\alpha_1 = \frac{T_1}{I_1} = \frac{0.5}{mR_1^2} = \frac{0.5}{1*0.5^2} = 2 rad/s^2$

$\alpha_2 = \frac{T_2}{I_2} = \frac{F_2}{mR_2^2} = \frac{F_2}{1*1^2} = F_2 rad/s^2$

For the 2nd wheel to have the same angular acceleration, its force must be

$\alpha_1 = \alpha_2$

$2 = F_2$

$F_2 = 2N$

6 0

3 years ago

A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an a

lions [1.4K]

Answer:

Approximately $4.61\times 10^{3}\; {\rm N}$ upwards (assuming that $g = 9.81\; {\rm m\cdot s^{-2}}$ .)

Explanation:

External forces on this astronaut:

Weight (gravitational attraction) from the earth (downwards,) and
Normal force from the floor (upwards.)

Let $(\text{normal force})$ denote the magnitude of the normal force on this astronaut from the floor. Since the direction of the normal force is opposite to the direction of the gravitational attraction, the magnitude of the net force on this astronaut would be:

$\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ .

Let $m$ denote the mass of this astronaut. The magnitude of the gravitational attraction on this astronaut would be $(\text{weight}) = m\, g$ .

Let $a$ denote the acceleration of this astronaut. The magnitude of the net force on this astronaut would be $(\text{net force}) = m\, a$ .

Rearrange $\begin{aligned}(\text{net force}) &= (\text{normal force}) - (\text{weight})\end{aligned}$ to obtain an expression for the magnitude of the normal force on this astronaut:

$\begin{aligned}(\text{normal force}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= m\, (a + g) \\ &= 80.9\; {\rm kg} \times (47.2\; {\rm m\cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 4.61 \times 10^{3}\; {\rm N}\end{aligned}$ .

3 0

2 years ago

((Bruv pls hurry on test)) Radioisotopes often emit alpha particles, beta particles, or gamma rays. The distance they travel thr

Jlenok [28]

Answer:

A,B,,G

Explanation:

got it right on edg

3 0

3 years ago

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