Under what conditions can calcium bromide conduct electricity

how many equivalent resonance structures can you draw for sulfate where the formal charges a minimized (like in the previous que

ch4aika [34]

There isn't a most favorable equivalent resonance of the Sulfate ion because they are all identical in charge and there is no change in Electronegativity between the Oxygen atoms.

What is atom?

An atom is a particle of count that uniquely defines a chemical element. Atoms include a critical nucleus surrounded with the aid of using one or greater negatively charged electrons. The nucleus is undoubtedly charged and carries one or greater quite heavy debris referred to as protons and neutrons.

Therefore, There isn't a most favorable equivalent resonance of the Sulfate ion because they are all identical in charge and there is no change in Electronegativity between the Oxygen atoms.

To learn more about atom refer the given link:-
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8 0

8 months ago

How many grams of calcium hydroxide is produced from 9.4 g of calcium chloride in this balanced

Yuliya22 [10]

Answer:

6.27 [gr].

Explanation:

the required mass can be calculated as:

m[Ca(OH)₂]=M[Ca(OH)₂]*m[CaCl₂]/M[CaCl₂], where M - molar mass [gr/mol], m - mass [gr];

m[Ca(OH)₂]=9.4*74/111≈6.2(6) [gr].

7 0

1 year ago

What is the name of this hydrocarbon?

jenyasd209 [6]

Answer:

2-methylebutane

Explanation:

it is a hydrocarbon and there is a specific Rule for its nomenclature.

that is known as IUPAC naming system. According to it

The compound that has all single bonds name ends on ane.
Names according to the number of Carbons,

* For one carbon compound it is known as methane,

* For 2 ethane,

* For 3 propane

* For 4 Butane and so on.

select the longest chain of compound
Start numbering with lowest substituted position at carbon
branch compound name as Iso and neo as whole

So keeping in mind the compound can be named as

2-methylebutane

As the longest chain contain four carbon atoms so it will name as butane
The substitution of methyl group is on C-2

*Note: it can also named as isopantane as it is branched and have five carbons but it could not be 3-isopentane.

5 0

2 years ago

Read 2 more answers

1) A car is traveling down the interstate at 37.1 m/s. The driver sees a cop and quickly slows down. If the driver slows to 29.8

WITCHER [35]

1)

The acceleration of the car is the rate of change of velocity of the car; it can be calculated as:

$a=\frac{v-u}{t}$

where

u is the initial velocity

v is the final velocity

t is the time taken for the velocity of the car to change from u to v

In this problem, for this car we have:

u = 37.1 m/s

v = 29.8 m/s

t = 3 s

So, the acceleration is:

$a=\frac{29.8-37.1}{3}=-2.43 m/s^2$

2)

The work done in lifting the box is equal to the potential energy transferred to the box during the process; it is given by:

$W=Fd$

where

F is the force applied

d is the displacement of the box

Here we have:

F = 87.3 N is the force applied

d = 2.04 m is the displacement of the box

So, the work done to lift the box is:

$W=(87.3)(2.04)=178.1 J$

3)

The power is the rate of work done per unit time. It is calculated as:

$P=\frac{W}{t}$

where

W is the work done

t is the time taken to do the work

For the child in this problem, we have:

W = 1250 J is the work done by the child running up the stairs

P = 267 W is the power used

Therefore, re-arranging the equation, we find the time taken:

$t=\frac{W}{P}=\frac{1250}{267}=4.68 s$

4)

The kinetic energy of an object is the energy possessed by the object due to its motion. Mathematically, it is given by

$KE=\frac{1}{2}mv^2$

where

m is the mass of the object

v is its speed

For the rabbit in this problem, we have:

m = 8.642 kg is the mass of the rabbit

KE = 125.6 is its kinetic energy

Solving the formula for v, we find the speed of the rabbit:

$v=\sqrt{\frac{2KE}{m}}=\sqrt{\frac{2(125.6)}{8.642}}=5.4 m/s$

5)

The efficiency of a machine is the ratio between the energy produced in output by the machine and the work done in input. Mathematically, it is given by

$\eta = \frac{E_{out}}{W_{in}}\cdot 100$

where

$E_{out}$ is the energy in output

$W_{in}$ is the work in input

For the machine in this problem,

$W_{in}=120 J$ is the work in input

$E_{out}=93 J$ is the energy in output

Therefore, the efficiency of this machine is:

$\eta=\frac{93}{120}\cdot 100=77.5\%$

6)

During a collision, the total momentum of the system is always conserved before and after the collision. So we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 =(m_1+m_2)v$

where

$m_1=212 kg$ is the mass of the first car

$u_1=8.00 m/s$ is the initial velocity of the first car

$m_2=196 kg$ is the mass of the 2nd car

$u_2=6.75 m/s$ is the initial velocity of the 2nd car

$v$ is the final velocity of the two cars stuck together (after the collision, they move together)

Solving the equation for v, we find:

$v=\frac{m_1 u_1 +m_2 u_2}{m_1 +m_2}=\frac{(212)(8.00)+(196)(6.75)}{212+196}=7.40 m/s$

7)

The relationship between speed, frequency and wavelength of a wave is given by the wave equation:

$v=f\lambda$

where

v is the speed of the wave

f is the frequency of the wave

$\lambda$ is the wavelength

For the wave in the string in this problem we have:

$\lambda=0.23 m$ (wavelength)

f = 12 Hz (frequency)

So, the speed of the wave is:

$v=(12)(0.23)=2.76 m/s$

8)

The relationship between frequency and wavelength for an electromagnetic wave is given by

$c=f\lambda$

where:

c is the speed of light in a vacuum

f is the frequency of the wave

$\lambda$ is the wavelength of the wave

For the blue light in this problem, we have

$f=6.2\cdot 10^{14}Hz$ (frequency)

while the speed of light is

$c=3.0\cdot 10^8 m/s$

So, the wavelength of blue light is:

$\lambda=\frac{c}{f}=\frac{3.0\cdot 10^8}{6.2\cdot 10^{14}}=4.8\cdot 10^{-7} m$

9)

The sound wave in this problem travels with uniform motion (=constant velocity), therefore we can use the following equation:

$d=vt$

where

d is the distance covered by the wave

v is the speed of the wave

t is the time elapsed

In this problem:

v = 343 m/s is the speed of the sound wave

t = 0.287 s is the time elapsed

So, the distance covered by the wave is

$d=(343)(0.287)=98.4 m$

3 0

3 years ago

Glaciers also _____ materials in new places when they melt.

natali 33 [55]

Deposits

Explanation:

Glaciers also deposits materials in new places when they melt.

Glaciers are made up of snow flakes that has compressed through time.
In temperate and polar regions where they are prevalent, they are powerful agents of denudation.
They can erode, transport and deposit earth materials in places.
When a glacier retreats by melting, it deposit some of its materials in new places.
Most of this sediment are called tillites.
They are made up of unsorted materials of different size grains.

learn more:

Metamorphic rock brainly.com/question/869769

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8 0

3 years ago