The mole ratio of iron to copper is 1 : 1, thus, 1.31 g of iron is required to produce 1.5 g of copper.
<h3>What is the equation of the reaction between iron and copper(ii) sulfate?</h3>
The reaction between iron and copper(ii) sulfate is a redox displacement reactions in which copper is displaced from its salt by iron.
The equation of the reaction is given below:
The mole ratio of both reactants and product is 1 : 1
molar mass of copper sulfate = 160 g
molar mass of Cu = 64
molar mass of iron = 56 g
- mole ratio of iron to copper = 1 : 1
moles of Cu in 1.5 g = 1.5/64 = 0.00234
mass of iron required = 0.00234 × 56 = 1.31 g of iron
Therefore, from the mole ratio of iron to copper, 1.31 g of iron is required to produce 1.5 g of copper.
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