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Viefleur [7K]
3 years ago
11

Solutions of aluminum nitrate and sodium sulfate react to form sodium nitrate and aluminum sulfate. Classify this reaction.

Chemistry
1 answer:
Temka [501]3 years ago
4 0
C is the correct answer. Double displacement reaction, also called as metathesis, is a type of reaction wherein two compounds react to form new compounds. This case the cations and the anions of the reactants replace each other forming the new compounds.
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What is the H+ concentration for an aqueous solution with pOH = 4.01 at 25 ∘C? Express your answer to two significant figures an
EleoNora [17]

I believe pH = -log[H+]

Also, 14 = pH + pOH

Therefore pH = 14 - pOH

pH = 14 - 4.01

pH = 9.99

9.99 = -log[H+]

Solve for H+

5 0
3 years ago
Which of the following elements is the smallest?
Oliga [24]

Answer:

Explanation:

The atomic radius of elements are used to estimate the sizes of elements. The atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.

To solve this problem we will obtain the atomic radius values of the given elements from a standard atomic radius table;

          Si          111 pm

           P          98 pm

          Cl          79 pm

            S           87pm

pm = picometer

We see that chlorine has the least atomic radius

7 0
3 years ago
Read 2 more answers
A negative △H means an exothermic reaction.<br><br> True<br> False
Nostrana [21]
Your answer is False I think
6 0
3 years ago
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form. How many grams of water form
DerKrebs [107]

Answer:

18 grams of water

Explanation:

The Balance Chemical Reaction is as follow,

                     2 NH₄NO₃    →    2 N₂  +  O₂  +  4 H₂O

According to Equation,

                     160 g (2 moles) NH₄NO₃ produces  =  72 g (4 moles) of H₂O

So,

                     40 g of NH₄NO₃ will produce  =  X g of H₂O

Solving for X,

                     X =  (40 g × 72 g) ÷ 160 g

                     X  =  18 g of H₂O

<em>Hope This Helps!</em>

4 0
2 years ago
If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

5 0
3 years ago
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