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Viefleur [7K]
3 years ago
11

Solutions of aluminum nitrate and sodium sulfate react to form sodium nitrate and aluminum sulfate. Classify this reaction.

Chemistry
1 answer:
Temka [501]3 years ago
4 0
C is the correct answer. Double displacement reaction, also called as metathesis, is a type of reaction wherein two compounds react to form new compounds. This case the cations and the anions of the reactants replace each other forming the new compounds.
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Use the following chemical equation to answer the question. 4K(s) + O2(g) → 2 K2O(s). If a staff member at a laboratory has 12.0
Allushta [10]

Answer:14.5 grams of K2O

Explanation:

4 0
3 years ago
Which substance can not be broken down by a chemical change
tangare [24]
Well, an element is a substance that cannot be decomposed into a simpler substance by chemical change, so element is the answer you are probably looking for! Hope this helps!
7 0
3 years ago
What would be the most likely explanation if none of the tested paint samples had turned brown?
mariarad [96]

Answer:4/d

Explanation:

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7 0
2 years ago
Write a balanced equation and determine Eº for each of the following cells: a) Cr Cr3+||Ni2+|Ni b) (CF|C1,||MnO | Mn?)
Alexxx [7]

Answer:

Explanation:

Step 1: Write both half reactions

Cr / Cr3+ : oxidation  Cr(s) → Cr3+ + 3e-  

Ni2+ / Ni : reduction Ni2+ +2e- → Ni

Step 2: Balance reactions and look up the standard potential for the  half-reactions

2(Cr → Cr3+ + 3e-)    E° ox = 0.74 V

3(Ni2+ +2e- → Ni)     E° red = -0.25 V

2Cr + 3Ni2+ +6e- → 2Cr3+ +6e- + 3Ni

E°cell = E° red + E° ox  = -0.25 + 0.74  = 0.49

E = E ° − 0.0257 V /n * ln Q  = E ° − 0.0257 V /n  *l n [ C r 3 + ]/ [ N i 2 + ]

With E° = 0.49 V

b)

Step 1: Write both half reactions

MnO4-/ Mn2+ (redution)   MnO4-  +8H+ +5e- ⇔ Mn2+ +4H2O

Cf ⇔ Cf2+ +2e-   (oxidation)   Cf ⇔ Cf2+ +2e-

Step 2: Balance reactions and look up the standard potential for the  half-reactions

MnO4-  +8H+ +10-e- ⇔ Mn2+ +4H2O    E° = 1.51 V

5Cf ⇔ 5 Cf2+ +10e-        E° =2.12 V

2 MnO4- + 16H+ + 5Cf ⇔ 2Mn2+ + 8H2O + 5Cf2+

E°cell = E° red + E° ox  = 1.51 + 2.12  = 3.63 V

E = E ° − 0.0257 V /n * ln Q  = E ° − 0.0257 V /n  *l n [ C f2 + ]/ [ Mno4- ]

With E° =3.63 V

7 0
3 years ago
What is another name for a beta minus (β–) particle?
Vikki [24]

Answer: Another name for beta-minus particle is electron.

Explanation: Beta-minus particle (_{-1}^0\beta ) is released during the beta-minus decay nuclear reaction.

In this nuclear reaction, a neutron gets converted into proton and electron. The electron released is the beta-minus particle.

The charge on these particles is -1 and mass of these particles is negligible.

5 0
3 years ago
Read 2 more answers
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