Use the picture above A.-15 B.-25 C.5 D.-45

3x+122=22x-11 i need help!

nasty-shy [4]

3x + 122 = 22x - 11

+11 + 11

3x + 133 = 22x

-3x -3x

133 = 19x

x = 7

5 0

2 years ago

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A rhombus is cut along the diagonals to make four triangles. Which three statements are correct for any rhombus? 1) All four tri

Nikolay [14]

Answer:

1). All four triangles are right-angled.

3.) All four triangles are congruent.

4) Area of a rhombus = 4 x area of one triangle.

Step-by-step explanation:

If a rhombus is cut into four triangles using diagonals, the three statements that would apply to any rhombus would be that 'all those four triangles would be right-angled,' 'the triangles would be congruent to one another,' and 'area of one triangle * 4 would be equal to the area of the rhombus.'

As we know, the diagonals bisect one another in a rhombus at 90° and the angles opposite to one another are equal. This proves that all four triangles constructed through the diagonals would be ≅ through SSS congruency and perpendicular to one another because the corresponding edges of the congruent triangles are also ≅ . Since the rhombus is divided into four equal parts, the area of one triangle into four would be equals to the area of the rhombus. Thus, options 1, 3, and 4 are the correct answers.

8 0

2 years ago

Find the perimeter and area of a rectangle with a length of 2 meters and a width of 3 meters

klasskru [66]

Let L and W be the length and width of the rectangle, respectively. To solve for the perimeter (P) and area (A), use the following formula:

P = 2 x (L + W)

A = L x W

Substituting the given value for the dimensions,

P = 2 x (2m + 3m) = 10 m

A = 2m x 3m = 6m^2

Therefore, the perimeter is 10m and the area is 6m^2.

4 0

2 years ago

In the given figure find the value of x and y? Show you works - Thank you!

Vaselesa [24]

EXPLANATION:

In ∆ ABC , ∠ABC = 40°

∠CAB = x°
& ∠ACD = 50°

∠ACD is an exterior angle formed by extending BC to D

We know that

The exterior angle of a triangle formed by extending one side is equal to the sum of the opposite interior angles.

∠ACD = ∠CAB + ∠ABC

⇛50° = x° + 40°

⇛x° = 50°-40°

and

In ∆ ACD , AC = CD

⇛ ∠CDA = ∠CAD

Since the angles opposite to equal sides are equal.

Let ∠CDA = ∠CAD = A°

We know that

The sum of all angles in a triangle is 180°

In ∆ ACD,

∠CDA +∠CAD + ∠ACD = 180°

A°+A°+50° = 180°

⇛2A°+50° = 180°

⇛2A° = 180°-50°

⇛2A° = 130°

⇛A° = 130°/2

⇛A° = 65°

now,

∠CDA = ∠CAD = 65°

∠BAC + ∠CAD+y = 180°

Since angles in the same line

10°+65°+y = 180°

⇛75°+y =180°

⇛y = 180°-75°

Answer: Hence, the value of “x” & “y” will be 10° and 105° respectively.

4 0

2 years ago

Plz simplify this expression: 5x(x-4)

Bas_tet [7]

Hello! You can answer this question by using the distributive property. Basically

a(b+c) = a(b) + a(c)

Let's apply it to this expression:

5x(x-4)
=5x(x)-5x(-4)
$=5x^{2} -20x)$

8 0

2 years ago

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