(a) The height of the cliff will be 8.26 meters.
(b) The time would it take to reach the ground will be 0.717 sec.
<h3>What is velocity?</h3><h3 />
The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.
(a) The height of the cliff will be 8.26 meters.
According to Newton's second equation of motion
Hence The height of the cliff will be 8.26 meters.
(b)The time would it take to reach the ground will be 0.717 sec.
We must have the final velocity to find the time so;
According to Newton's third equation of motion ;
Hence the time would it take to reach the ground will be 0.717 sec.
To learn more about the velocity refer to the link ;
brainly.com/question/862972
Displacement is the distance and direction from the start point to the end point. Our runner finished exactly where he started. His displacement is zero.
Answer: 16.3 seconds
Explanation: Given that the
Initial velocity U = 80 ft/s
Let's first calculate the maximum height reached by using third equation of motion.
V^2 = U^2 - 2gH
Where V = final velocity and H = maximum height.
Since the toy is moving against the gravity, g will be negative.
At maximum height, V = 0
0 = 80^2 - 2 × 9.81 × H
6400 = 19.62H
H = 6400/19.62
H = 326.2
Let's us second equation of motion to find time.
H = Ut - 1/2gt^2
Let assume that the ball is dropped from the maximum height. Then,
U = 0. The equation will be reduced to
H = 1/2gt^2
326.2 = 1/2 × 9.81 × t^2
326.2 = 4.905t^2
t^2 = 326.2/4.905
t = sqrt( 66.5 )
t = 8.15 seconds
The time it will take for the rocket to return to ground level will be 2t.
That is, 2 × 8.15 = 16.3 seconds
Answer:
from food eaten (i.e contain carnlbohyadrates)
