Answer:
1.25 s
Explanation:
We are given that
Initial velocity of boy=u=0
Time=0.883 s
Let x be the total distance covered by boy in entire trip.
s=
We know that

Where 
Substitute the values


m
Again using the above formula




Hence, 1.25 s passes during his entire tripe from the top down to the water.
The correct answer is <span>The car has both potential and kinetic energy, and it is moving at 24.6 m/s.</span>
True. Also stretches shoulders and other things
Answer:
6.69m/s,529N
Explanation:
Now we have 3 forces acting on the boy at its least point, the two tensions on the string and its weight. The tensions are acting upwards why its weight is acting downwards.
Hence the net force causes the child to swing in a circular fashion without skidding off the swing.
This net force is the centripetal force.
The weight of the child is mass × g
35×9.8=343N
The net force = 436+436-343 = 529N
The centripetal force is defined mathematically as;
F = mass × velocity square/ length of string.
Hence 529 = 35V^2/2.96
V^2 = 529×2.96/35 =44.7383
V=√44.7383 =6.69m/s
B. The force exerted by the seat on the child is the net force which keeps the boy from falling.
529N