All categories

2 years ago

One of the examples of homologous series is given below:

Chemistry

1 answer:

Rus_ich [418]2 years ago

4 0

<h3>Answer & Explanation:</h3>

Homologous series: Homologous series is the series in which the functional group of any compound and their chemical properties are similar, the difference between any two successive members is same.

Above homologous series is of Alkanol

$\tiny\sf \: general \: formula \: for \: Alkanol \rightarrow C_nH_{2n+2}O$

Above homologous series is differed by methylene (-CH2-) group. hence the mass diffrence between them would be the mass of -CH2- group.

$\small \sf \: CH_2 = = 12+1+1 = 14 \: a.m.u. \\ \hline$

The compound X is next to CH3CH2OH hence, X will have molecular formula CH3CH2CH2OH which is obtained by addition of a methylene group.

$\tiny\: the \: compound \: x \: (n = 3) \: have \: general formula =C_3H_{8}O \\ \small \sf \: The \: molecular \: mass \: of \: X =3 \times 12 + 8 \times 1 + 16 \\ \sf = 60 \: a.m.u$

The reason behind the highest boiling point of butanol is his molecular mass, the main reason is the surface area, as the molecular mass increases surface area also increases which lead to increase in the vanderwall forces, due to which boiling point of compound increases. the same compound having least solubility is due to lyophilic/Hydrophobic ( tendency to get dissolved in non aqueous solution) increases & solubility of compound in polar solvents decreases.

$\small \sf \: Thanks \: for \: joining \: brainly \: community! \\ \hline$

You might be interested in

A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under

sukhopar [10]

Answer:

$\rho _2=0.22g/L$

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

$PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT$

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

$\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}$

It means we can compute the final density as shown below:

$\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}$

Now, we plug in to obtain:

$\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L$

Regards!

8 0

3 years ago

A drought has affected an ecosystem. Many plants have died due to lack of water. What do you think will happen ti the other orga

IceJOKER [234]

I think eventually other organisms will die out as well because many herbivores feed on plants for survival, and many other animals feed on these herbivores for survival and so on (this causes a chain reaction because there is a lack of available food)

5 0

3 years ago

The ionization energies for removing successive electrons from sodium are 496 kJ/mol, 4562 kJ/mol,

ddd [48]

Answer:

Explanation:

The high jump of ionization energy indicates that we are trying to remove electron from noble gas configuration state.

The ionization energy data specifies that the Elements are from group 1 at period 3 or greater.

Removing the first electron require 496 kJ and the second ionization energy jump significantly due to the removal of electron from the noble gas configuration which is logical because electron try to maintain the especially stable state.

3 0

3 years ago

Matter is everywhere around us. Make a list by nameof fifteen different kinds of matter that you encounter every day. Your list

Dmitry [639]

Solids: wood, plastic, metals

Liquids: water (H2O), soap, juice, milk

Gases: Air, water vapour (H2O), carbon dioxide (CO2)

An element: gold, silver, aluminum, copper, nickel, iron, nitrogen in the air

A compound: salt (NaCl), carbon dioxide (CO2)

A homogenous mixture: air, water with sugar or salt dissolved in it

A heterogeneous mixture: orange juice with pulp, cereal in milk

Pure substances: diamond, water, salt, baking soda, sugar

6 0

3 years ago

Give reasons. a. Troposphere is affected maximum by human activities.

NNADVOKAT [17]

Answer:

it is where the ozone layer is locate which is affected by human activities

5 0

3 years ago